Let x = the length of the shorter piece
x+x+16=50in
2x=50-16
2x=34
x=17
Then
x+16=17+16
x+16=33
Subtract 16 from both sides
The lengths are 17in and 33in
Answer:
4: <5= 115°
5: <2= 115°
6: <6= 115°
10: <1= 30°
11: <4= 30°
12: <6= 150°
Step-by-step explanation: Hope this helped
First start by multiplying:
-6/15 + 5/2 -3/30
then u can simplify the fractions, -6/15=-2/5 and -3/30=-1/10
-2/5 + 5/2 - 1/10, now find a common denominator in this case 10
-4/10 + 25/10 - 1/10
now add and subtract normally
answer:20/10 or 2
In order to find the smallest amount of cardboard needed, you need to find the total surface area of the rectangular prism.
Therefore, you need to understand how the cans are positioned in order to find the dimensions of the boxes: two layers of cans mean that the height is
h = 2 · 5 = 10 in
The other two dimensions depend on how many rows of how many cans you decide to place, the possibilities are 1×12, 2×6, 3×4, 4×3, 6×2, 12×1.
The smallest box possible will be the one in which the cans are placed 3×4 (or 4×3), therefore the dimensions will be:
a = 3 · 3 = 9in
b = 3 <span>· 4 = 12in
Now, you can calculate the total surface area:
A = 2</span>·(a·b + a·h + b·h)
= 2·(9·12 + 9·10 + 12·10)
= 2·(108 + 90 + 120)
= 2·318
= 636in²
Hence, the smallest amount of carboard needed for the boxes is 636 square inches.
