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3 years ago

Complete the steps to find the value of x. 72° (7x + 24)

Mathematics

1 answer:

Elis [28]3 years ago

8 0

Answer:

x=6.86°

firstly set them equal

to each other

(7x+24)=72°

subract 24 from both sides:

7x=48°

divide both sides by 7 :

x=6.857.....

this can be rounded to :

x=6.86°

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Show proof of how you got it

yulyashka [42]

4x + 8

To distribute, multiply 4 by x and 4 by 2.

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3 years ago

Which number should each side of the equation 34x=9 be multiplied by to produce the equivalent equation of x = 12?

grin007 [14]

3/4x = 9....multiply both sides by 4/3...eliminating the 3/4 on the left side
x = 9 * 4/3
x = 36/3
x = 12

3 0

3 years ago

Read 2 more answers

it took milo and myron 315 hours to fly their saucer from mars to earth. milo piloted the saucer 21 times longer than myron did.

PtichkaEL [24]

Mylo+myron =315 hours
Assume myron is (x) hours
Then milo 21+x
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7 0

3 years ago

The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.

ozzi

Answer:

The 80% confidence interval for the mean usage of water is between 18.4 and 18.6 gallons per day.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.8}{2} = 0.1$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.1 = 0.90$ , so $z = 1.28$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.28*\frac{2.3}{\sqrt{717}} = 0.1$

The lower end of the interval is the sample mean subtracted by M. So it is 18.5 - 0.1 = 18.4 gallons per day.

The upper end of the interval is the sample mean added to M. So it is 18.5 + 0.1 = 18.6 gallons per day.

The 80% confidence interval for the mean usage of water is between 18.4 and 18.6 gallons per day.

6 0

3 years ago

What is the extraneous solution found in solving the equation log2 4x + log₂ (x + 1) = 3

yan [13]

Answer:

x = -2

Step-by-step explanation:

We are given the logarithmic base 2 equation of:

$\displaystyle{\log_2 (4x) + \log_2 (x+1) = 3}$

Apply logarithm property of addition where:

$\displaystyle{\log_a M + \log_a N = \log_a MN}$

Therefore, we will write new equation as:

$\displaystyle{\log_2 [4x(x+1)] = 3}$

Apply logarithm to exponential form using:

$\displaystyle{\log_a M = N \to a^N = M}$

Thus, another new rewritten equation is:

$\displaystyle{2^3 = 4x(x+1)}\\\\\displaystyle{8 = 4x(x+1)}\\\\\displaystyle{2=x(x+1)}$

Expand the expression in and arrange the terms in quadratic expression:

$\displaystyle{2=x^2+x}\\\\\displaystyle{0=x^2+x-2}\\\\\displaystyle{x^2+x-2=0}$

Solve for x:

$\displaystyle{(x+2)(x-1)=0}\\\\\displaystyle{x=-2,1}$

These are potential solutions to the equation. To find extraneous solution, you’ll have to know the domain of logarithm function. We know that logarithm’s domain is defined to be greater than 0. Henceforth, anti-logarithm must be greater than 0.

( 1 ) 4x > 0, x > 0

( 2 ) x + 1 > 0, x > -1

Therefore, our anti-log must be greater than 0, so any solutions that are equal or less than 0 will be considered as extraneous solution.

Hence, x = -2 is the extraneous solution.

7 0

2 years ago