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likoan [24]
2 years ago
15

What do you know about the sun's motion based on the nebular hypothesis model?

Chemistry
2 answers:
Effectus [21]2 years ago
5 0
I think the answer is C
Ierofanga [76]2 years ago
4 0
I think the answer is C im not sure
You might be interested in
How many grams are in 8.3 moles of CaCl2?
r-ruslan [8.4K]

Answer:

(8.3×40)+(8.3×71)

921.3grames

3 0
2 years ago
Read 2 more answers
If an atom has 5 protons, how many electrons does it have?
IRISSAK [1]

Answer:

5

Explanation:

An atom has the same number of protons and electrons

8 0
3 years ago
Read 2 more answers
Find the [h3o ] in a sauvignon blanc with a ph of 3.24.
KengaRu [80]
Hello!

The H₃O⁺ concentration can be found using the definition of pH and clearing the equation for [H₃O⁺]. The solution has a pH lower than 7, so the Sauvignon Blanc is acid. The calculation for [H₃O⁺] is shown below:

pH=-log [H_3O^{+}]

[H_3O^{+}]= 10^{-pH}=10^{-3,24}=0,00058M

So, the concentration of H₃O⁺ in a Sauvignon Blanc with a pH of 3,24 is 0,00058 M

Have a nice day!
7 0
2 years ago
A group 2 metal carbonate has a mass of 84 g/mol. Identify the group 2 metal X using its chemical formula.
zepelin [54]

Answer:

Magnesium

0.003mole

Explanation:

The problem here entails we find the metal in the carbonate.

 For group 2 member, let the metal  = X;

 The carbonate is XCO₃;

 If we sum the atomic mass of the elements in the metal carbonate, we should arrive at 84g/mol

 Atomic mass of C = 12g/mol

                            O  = 16g/mol

 Atomic mass of X + 12 + 3(16)  = 84

  Atomic mass of X  = 84 - 60  = 24g/mol

The element with atomic mass of 24g is Magnesium

B.

Number of moles in 0.3g of CaCO₃:

     Molar mass of CaCO₃   = 40 + 12 + 3(16)  = 100g/mol

 Number of moles = \frac{mass}{molar mass}  

 Number of moles  = \frac{0.3}{100}   = 0.003mole

7 0
3 years ago
What is the new concentration of 25.0mL added to 125.0mL of 0.150M
____ [38]

Answer:

The new concentration is 0.125 M.

Explanation:

Given data:

Initial volume V₁ = 125.0 mL

Initial molarity M₁ = 0.150 M

New volume V₂ = 25 mL +125 mL = 150 mL

New concentration M₂ = ?

Solution:

M₁V₁    =    M₂V₂

0.150 M × 125 mL = M₂ × 150 mL

M₂ = 0.150 M × 125 mL / 150mL

M₂ = 18.75 M.mL/150 mL

M₂ = 0.125 M

The new concentration is 0.125 M.

8 0
3 years ago
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