Compare the the volumes and densities of two pieces of lead: one with a mass of 25 g and the other with a mass of 75 g.

Morgan and Lily are studying the density of substances. After determining a block's mass and volume, they determine its density

slavikrds [6]

The formula of Density is known as:

Density = mass/volume

Units: g/cm^3

Hope this helps!

3 0

3 years ago

the reaction of aluminum with chlorine gas is shown 2Al + 3Cl2 -> 2AlCl3 based on this equation how many molecules of chlorin

Vanyuwa [196]

45 molecules of chlorine gas (Cl₂) are needed to react with 30 atoms of aluminum (Al)

The balanced equation for the reaction is given below:

2Al + 3Cl₂ —> 2AlCl₃

From the balanced equation above,

2 atoms of Al required 3 molecules of Cl₂.

With the above information, we can determine the number of molecules of Cl₂ needed to react with 30 atoms of Al. This can be obtained as follow:

From the balanced equation above,

2 atoms of Al required 3 molecules of Cl₂.

Therefore,

30 atoms of Al will require = $\frac{30 * 3}{2}\\$ = 45 molecules of Cl₂.

Thus, 45 molecules of chlorine gas (Cl₂) are needed to react with 30 atoms of aluminum (Al)

Learn more: brainly.com/question/24918379

3 0

2 years ago

139%

GaryK [48]

<u>Answer:</u>

The percent composition of this compound is 94%

<u>Explanation:</u>

The reaction can be formed as

$2 \mathrm{Fe}+3 \mathrm{Cl}_{2} \rightarrow 2 \mathrm{FeCl}_{3}$

$\frac{\text { Weight of } \mathrm{Cl}_{2}}{\text { 3* Molar Mass of } \mathrm{Cl}_{2}}=\frac{\text { Weight of } \mathrm{Fe}}{2 * \text { Molar Mass of Fe }}$

$\frac{\text { Weight of } \mathrm{Cl}_{2}}{3 *(2 * 35.5)}=\frac{3.56}{2 * 55.8}$

$\text { Weight of } C l_{2}=\frac{3.56 * 3 * 71}{2 * 55.8}=6.79 \mathrm{g}$

$\mathrm{n}\left(\mathrm{Cl}_{2}\right)=\mathrm{m}\left(\mathrm{Cl}_{2}\right) / \mathrm{M}\left(\mathrm{Cl}_{2}\right)=6.79 / 71=0.1 \mathrm{m}$

$\mathrm{n}(\mathrm{Fe})=\mathrm{m}(\mathrm{Fe}) / \mathrm{M}(\mathrm{Fe})=3.56 / 55.8=0.06 \mathrm{m}$

Based on no. of iron reacted,

$\mathrm{n}(\text { moles of } \mathrm{Fe})=\mathrm{n}\left(\text { moles of } \mathrm{FeCl}_{3}\right)$

n = m/M

$\mathrm{m}\left(\mathrm{FeCl}_{3}\right)=\mathrm{n}^{*} \mathrm{M}=0.06^{*} 162.5=9.75 \mathrm{g}$

% composition of $FeCl_3$

= $(9.75 / 10.39)^{*} 100$

= 94%

6 0

3 years ago

When a solution is considered to have a high concentration of hydrogen ions (H+) is also considered to be?

charle [14.2K]

Answer: option A. acidic

Explanation: acidic solution is characterized by the presence of Hydrogen ion.

6 0

2 years ago

Transamination of an amino acid transfers an amine group to form an α‑keto acid and is catalyzed by transaminases. Some amino ac

iragen [17]

Answer:

Amino acids that fall under the first category are alanine, aspartate and glutamate. While amino acids that fall under the second category are glycine, valine, proline, leucine, isoleucine, methionine, serine, threonine, cysteine, asparagine, glutamine, phenylalanine, tryptophan, tyrosine, lysine, arginine and histidine

Explanation:

Alanine, a 3-carbon amino acid reacts with α-ketoglutarate, a 5-carbon ketoacid, to produce pyruvate, a 3-carbon compound which is one of the glycolytic products in aerobic respiration, and glutamate, a 5-carbon amino acid, with the aid of alanine transaminase (ALT). The amino group from alanine is transfered from the α-carbon of alanine to the α-carbon of the α-ketoglutarate.

Aspartate, a 4-carbon amino acid also reacts with α-ketoglutarate to form oxaloacetate, a 4-carbon ketoacid which is present as an intermediate in the citric acid cycle, and glutamate. The amino group transfer occurs between the α-carbon of aspartate and the α-carbon of α-ketoglutarate.

Unlike the presence of a ketoacid in the conversion of alanine and aspartate to their corresponding amino acids, glutamate conversion to α-ketoglutarate, an intermediate in the citric acid cycle, involves no ketoacids as an amino group acceptor from glutamate. The amino group is freely released as an ammonium ion. The reaction involves the presence of a cofactor, NAD+ or NADP+, water (H2O) and glutamate dehygrogenase (GDH).

Other amino acids involve several metabolic steps to be converted into glycolytic or citric acid intermediates.

7 0

2 years ago