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Stels [109]
1 year ago
11

Determine the ratio of moles of iron actually used to moles of new product actually formed. Does this molar ratio agree with the

ratio from the balanced chemical equation?​
equation 1.50g Cu 1 mole cu ÷ 63.5g Cu Fe ÷1 Cu 55.8gFe ÷ 1 mole = 1.32g Fe

Chemistry
1 answer:
KATRIN_1 [288]1 year ago
8 0

The mole ratio of iron to copper is 1 : 1, thus, 1.31 g of iron is required to produce 1.5 g of copper.

<h3>What is the equation of the reaction between iron and copper(ii) sulfate?</h3>

The reaction between iron and copper(ii) sulfate is a redox displacement reactions in which copper is displaced from its salt by iron.

The equation of the reaction is given below:

CuSO_4 + Fe \rightarrow FeSO_4 + Cu

The mole ratio of both reactants and product is 1 : 1

  • moles = mass/molar mass

molar mass of copper sulfate = 160 g

molar mass of Cu = 64

molar mass of iron = 56 g

  • mole ratio of iron to copper = 1 : 1

moles of Cu in 1.5 g = 1.5/64 = 0.00234

mass of iron required = 0.00234 × 56 = 1.31 g of iron

Therefore, from the mole ratio of iron to copper, 1.31 g of iron is required to produce 1.5 g of copper.

Learn more about mole ratio at: brainly.com/question/19099163

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Solution X is a strong base with a pH of 12. Solution X is mixed with solution Y,and the pH of the resulting mixture is 8.Based
myrzilka [38]

The strong Base with a pH of 12 is reduced by 4 units upon being added with solution Y. If you added a strong acid to the strong base, all ions are present in the solution, yes? So every OH- is neutralised by every H+ for example, meaning the resultant pH should be 7. The resultant pH is only 8 however, so solution Y must be a <em>weak acid </em>only!

5 0
3 years ago
What is the element with the symbol Ba?​
Vika [28.1K]

Answer:

Barium

Explanation:

-Atomic #56

-5th element inn group 2

- soft

- silvery alkaline earth metal

3 0
3 years ago
Read 2 more answers
A doctor's Order is 0.125 g of ampicillin. The liquid suspension on hand contains 250 mg/s. How many milliliters (mL) of the sus
Molodets [167]

Answer:

c) 2.5 mL

Explanation:

Solution

Doctors order = 0.125g

and

The liquid suspension concentration = 250 mg/5ml

= 0.250g/5ml

Or 0.05g/ml

Amount of ml of suspension required = 0.125g/(0.05g/ml) = 2.5ml

7 0
3 years ago
Copper oxide, CuO, reacts with hydrochloric acid, HCI, to produce copper chloride, CuCL2 and water
spayn [35]

Explanation:

El óxido de cobre (II), también llamado antiguamente óxido cúprico ({\displaystyle {\ce {CuO}}}{\displaystyle {\ce {CuO}}}), es el óxido de cobre con mayor número de oxidación. Como mineral se conoce como tenorita.

{\displaystyle {\ce {2Cu + O2 = 2CuO}}}{\displaystyle {\ce {2Cu + O2 = 2CuO}}}

Aquí, se forma junto con algo de óxido de cobre (I) como un producto lateral, por lo que es mejor prepararlo por calentamiento de nitrato de cobre (II), hidróxido de cobre (II) o carbonato de cobre (II):

{\displaystyle {\ce {2 Cu(NO3)2 = 2 CuO + 4 NO2+ O2}}}{\displaystyle {\ce {2 Cu(NO3)2 = 2 CuO + 4 NO2+ O2}}}

{\displaystyle {\ce {Cu(OH)2 (s) = CuO (s) + H2O (l)}}}{\displaystyle {\ce {Cu(OH)2 (s) = CuO (s) + H2O (l)}}}

{\displaystyle {\ce {CuCO3 = CuO + CO2}}}{\displaystyle {\ce {CuCO3 = CuO + CO2}}}

El óxido de cobre (II) es un óxido básico, así se disuelve en ácidos minerales tales como el ácido clorhídrico, el ácido sulfúrico o el ácido nítrico para dar las correspondientes sales de cobre (II):

{\displaystyle {\ce {CuO + 2 HNO3 = Cu(NO3)2 + H2O}}}{\displaystyle {\ce {CuO + 2 HNO3 = Cu(NO3)2 + H2O}}}

{\displaystyle {\ce {CuO + 2 HCl =CuCl2 + H2O}}}{\displaystyle {\ce {CuO + 2 HCl =CuCl2 + H2O}}}

{\displaystyle {\ce {CuO + H2SO4 = CuSO4 + H2O}}}{\displaystyle {\ce {CuO + H2SO4 = CuSO4 + H2O}}}

Reacciona con álcali concentrado para formar las correspondientes sales cuprato.

{\displaystyle {\ce {3 XOH + CuO + H2O = X3[Cu(OH)6]}}}{\displaystyle {\ce {3 XOH + CuO + H2O = X3[Cu(OH)6]}}}

Puede reducirse a cobre metálico usando hidrógeno o monóxido de carbono:

{\displaystyle {\ce {CuO + H2 = Cu + H2O}}}{\displaystyle {\ce {CuO + H2 = Cu + H2O}}}

{\displaystyle {\ce {CuO + CO = Cu + CO2}}}{\displaystyle {\ce {CuO + CO = Cu + CO2}}}

6 0
2 years ago
What is the mass of an osmium block that measures 6.70 cm × 9.20 cm × 3.30 cm? The density of osmium is given as 22.610 g/cm3. N
alexira [117]

Answer:

m= 4,599.145 g

Explanation:

Let m = mass, d = density and V = volume of the osmium block.

m = d x V

m = 22.610 g/cm3 x (6.70 x 9.20 x 3.3) cm3

m = 4,599.145 g

7 0
2 years ago
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