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I am Lyosha [343]
3 years ago
10

Please help me struggling

Mathematics
1 answer:
Liula [17]3 years ago
5 0

Answer:

Step-by-step explanation:

find the composition of g(x)=x−1 and  h(x)=\sqrt{x}

hence we will get,

(g∘h)(x)=g(h(x))= g(x−1)= f(√x)= -1+√x =  √x -1

Now to find f(g(h(x))),

f(x)=x4+6  and g(h(x))=√x -1

hence , putt g(h(x))  in f(x) ,

f(g(h(x)))=(\sqrt{x}-1)^{4}+6 -

Plzzzz Brain-list it  or subscribe to my channel  " ZK SOFT&GAMING"

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9x - 4= 2x + 3<br> -—-——-—-
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Answer:

x = 1

Step-by-step explanation:

9x−4=2x+3 Move all terms containing x to the left side of the equation.

7x−4=3 Move all terms not containing x to the right side of the equation.

7x=7 Divide each term by 7 and simplify. x = 1

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STALIN [3.7K]

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One more math question! Thanks!
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Find the average value of the function f(t)=(t-2)^2 on [0,6]
pentagon [3]

Answer:

2

Step-by-step explanation:

The "average value of function f(x) on interval [a, b] is given by:

                      f(b) - f(a)

ave. value = ---------------

                         b - a

Here f(t)=(t-2)^2.

Thus, f(b) = (b - 2)^2.  For b = 6, we get:

          f(6) = 6^2 - 4(6) + 4, or f(6) = 36 - 24 + 4 = 16

For a = 0, we get:

           f(0) = (0 - 2)^2 = 4

Plugging these results into the ave. value function shown above, we get:

                      16 - 4

ave. value = ------------ = 12/6 = 2

                         6 - 0

The average value of the function f(t)=(t-2)^2 on [0,6] is 2.


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sleet_krkn [62]

Answer:

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Step-by-step explanation:

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