St=d
s=d/t
t=d/s
so we have several things:
distance of alfredo
speed of alfredo
time of alredo
distance of louisa
speed of louisa
time of louisa
we will represen them as follows
distance of alfredo=d1
speed of alfredo=s1
time of alredo=t1=2=t2
distance of louisa=d2
speed of louisa=s2
time of louisa=t2=2=t1
d=distance
t=time
total d=15 miles
t=2 hours
they both walk towards each other
louisa's speed is 1 mile per hour more than Alfredo so s2=s1+1
so we also have
d1+d2=15
s2=s1+1
t1=t2=2
we want to solve for s1 and s2
d=st
d1=(s1)(2)
d2=(s2)(2)
subsitute s1+1 for s2
d2=(s1+1)(2)
put back ino equation
(s1)(2)+(s1+1)(2)=15
distribute
2s1+2s1+2=15
2(s1)+2(s1)+2=15
add like terms
4(s1)+2=15
subtract 2 from both sides
4(s1)=13
divide both sides by 4
s1=13/4=3 and 1/4 mph
s2=s1+1
s2=3 and 1/4
s2=4 and 1/4 mph
check
d=st
t=2
alfredo's distance=(3 and 1/4) times 2=6 and 1/2
louisa's distance=(4 and 1/4) times 2=8 and 1/2
6 and 1/2+8 and 1/2=6+1/2+8+1/2=14+1=15
Alfredo's walking speed=3 and 1/4 miles per hour
Louisa's walking speed=4 and 1/4 miles per hour
aka
Alredospeed=3.25 mph
Louisaspeed=4.25 mph
I believe the answer is 5:6
Answer:
do you need help with the L and P???????
Step-by-step explanation:
I believe it is A because line segment AC is equal to line segment BD, and AE and BF are also the same
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Answer: c=38.89
b=29.79
<A=40
Explanation:
I hope this helped!
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