The area of a circle is Pi * R^2 (or R * R).
Since we have our radius, R, we can solve.
With our given answer choices, we do not need to multiply R by Pi, instead we will square R, as that's our only option.
4.5 x 4.5 = 20.25.
Our area is now 20.25Pi.
Your answer is C.) 20.25Pi.
I hope this helps!
Option A
Elena need to ride around the loop four or more times
<em><u>Solution:</u></em>
Given that Elena plans to ride her bicycle 5 miles to a park and then ride several times around a loop in the park that is 3 miles long
Then she will ride the same way home
She wants to ride a total of at least 22 miles
<em><u>Given inequality is:</u></em>
3t + 10 > 22
Where "t" is the number of times Elena rides around the loop
<em><u>Solve fot "t" in given inequality</u></em>
3t + 10 > 22
Subtract 10 both sides
3t + 10 - 10 > 22 - 10
3t > 12
Divide by 3 both sides
t > 4
The solution is all real numbers greater than or equal to 4
Which means 4 or more times
Therefore, Option A is correct.
Answer: m = 10
.........................
Answer:
BE=15
Step-by-step explanation:
Since E is the center, BE=2x+1
And AC is 6x-12 with E being a midpoint.
Since AC is 2 segments and BE is only 1 then you multiply 2x+1 by 2 so that
you can find x. You multiply 2x+12 by 2 because E is the midpoint so that means ED is the same value as BE
6x-12=4x+2
BD=AC
6x-4x-12=2
2x=2+12
2x=14
x=7
BE= 2x+1
2(7)=14+1=15
Answer:
D. $31,337.27
Step-by-step explanation:
We have that the initial amount of the loan is $5500.
Miranda took the loan for 4 years. So, the total present value is $5500×4 = $22,000.
The rate of interest on the loan is 7.5% i.e. 0.075 and it was for the duration of 10 years.
Also, it is given that the loan was compounded annually.
We have the formula as,
i.e. ![PV=\frac{P\times [1-(1+\frac{r}{n})^{-t\times n}]}{\frac{r}{n}}](https://tex.z-dn.net/?f=PV%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7B-t%5Ctimes%20n%7D%5D%7D%7B%5Cfrac%7Br%7D%7Bn%7D%7D)
Substituting the values, we get,
i.e. ![PV=\frac{P\times [1-(1+\frac{0.075}{12})^{-10\times 12}]}{\frac{0.075}{12}}](https://tex.z-dn.net/?f=PV%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281%2B%5Cfrac%7B0.075%7D%7B12%7D%29%5E%7B-10%5Ctimes%2012%7D%5D%7D%7B%5Cfrac%7B0.075%7D%7B12%7D%7D)
i.e. ![22000=\frac{P\times [1-(1+0.00625)^{-120}]}{0.00625}](https://tex.z-dn.net/?f=22000%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281%2B0.00625%29%5E%7B-120%7D%5D%7D%7B0.00625%7D)
i.e. ![22000=\frac{P\times [1-(1.00625)^{-120}]}{0.00625}](https://tex.z-dn.net/?f=22000%3D%5Cfrac%7BP%5Ctimes%20%5B1-%281.00625%29%5E%7B-120%7D%5D%7D%7B0.00625%7D)
i.e. ![22000=\frac{P\times [1-0.4735]}{0.00625}](https://tex.z-dn.net/?f=22000%3D%5Cfrac%7BP%5Ctimes%20%5B1-0.4735%5D%7D%7B0.00625%7D)
i.e. 
i.e. 
i.e. 
i.e. 
Thus, the total lifetime cost to pay of the loans compounded annually = 261.16 × 120 = $31,339.2
Hence, the total cost close to the answer is $31,337.27
