Glucose exists in an equilibrium mixture of linear and cyclic forms. propose a mechanism to describe this facile interconversion
1 answer:
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Answer:
1-Fluoro-4-nitrobenzene
Step-by-step explanation:
Step 1. Identify the substituents on the ring,
The groups are <em>fluoro</em> and <em>nitro</em>. They have no priority as functional groups, so the base name is <em>benzene</em>.
Step 2. Identify their relative priorities.
F and NO₂ have no functional group priority, so we list them in alphabetical order. F has <em>alphabetical priority </em>over NO₂. The name becomes <em>fluoronitrobenzene</em>.
Step 3. Number the atoms of the ring.
The C atom bearing the F is <em>C1.</em> Count around the ring, and the NO₂ group is on <em>C4</em>.
Step 4. Name the compound.
Insert the locating numbers <em>immediately in front</em> of the substituents. Use <em>hyphens</em> to join letters to numbers.
The name becomes 1-fluoro-4-nitrobenzene.
Answer: Option (3) is the correct answer.
Explanation:
A molecule is polar when the net dipole moment of molecule is zero. When an electronegative atom is attached to an electropositive atom then the electronegative atom pulls the shared pair of electrons more towards itself.
As a result, the movement of electrons is more towards the electronegative atom and the dipole moment becomes zero. This will also induce partial positive and partial negative charge on electropositive and electronegative atom.
On the other hand, are covalent compounds and does not have a net zero dipole moment.
Thus, we can conclude that out of the given options represents a polar molecule.