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4 years ago

6

2. What is the relationship between the scientific method and bias? Explain in detail.

1 answer:

Margaret [11]4 years ago

4 0

The scientific method attempts to minimize the influence of bias or prejudice in the experimenter. Even the best-intentioned scientists can't escape bias. It results from personal beliefs, as well as cultural beliefs, which means any human filters information based on his or her own experience.

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The number of particles in 1 mole of hydrogen gas is ________.

ivanzaharov [21]

Hidrogen gas is a diatomic gas, this is H2, which means that one molecule of gas has two atoms (every molecule of hydrogen gas consists in H2).

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Therefore, the answer is one mole.

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3 years ago

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A gas balloon has a volume of 106.0 liters when the temperature is 25.0 °C and the pressure is 740.0 mm Hg. What will its volume

ipn [44]

Answer : The final volume of gas will be, 103.3 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 740.0 mmHg = 98.4 kPa

Conversion used : (1 mmHg = 0.133 kPa)

$P_2$ = final pressure of gas = 99.3 kPa

$V_1$ = initial volume of gas = 106.0 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $25.0^oC=273+25.0=298K$

$T_2$ = final temperature of gas = $20.0^oC=273+20.0=293K$

Now put all the given values in the above equation, we get:

$\frac{98.4kPa\times 106.0L}{298K}=\frac{99.3kPa\times V_2}{293K}$

$V_2=103.3L$

Therefore, the final volume of gas will be, 103.3 L

8 0

3 years ago

58. A cylinder of a gas mixture used for calibration of blood gas analyzers in medical laboratories contains 5.0% CO2, 12.0% O2,

erica [24]

<em><u>Answer and Explanation:</u></em>

$Greetings!$

$Let's~answer~your~question!$

$Partial ~pressure ~of ~gas ~can ~be ~directly~ calculated ~by ~multiplying ~the~ percentage\\ of~ pressure~ of~ gases~ to ~the ~total ~pressure.$

$\boxed{Pgas~ = ~P~total~ * \% ~P ~of ~gas}$

<em><u>For % of N2 gas: </u></em>

<em><u /></em> $100\% - (5\% + 12\%) = 83\% ~N2$ <em><u /></em>

<em><u /></em>

<em><u /></em> $PN_2 ~= ~146~ atm~ *~ 0.83 ~ = 121.18 ~atm$ <em><u /></em>

<em><u /></em> $PO_2 ~= ~146~ atm~ *~ 0.12~ = 17.52 ~atm$ <em><u /></em>

<em><u /></em> $~PCO_2~ = ~146~ atm ~* 0.05 = 7.3 ~atm$ <em><u /></em>

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4 years ago