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wariber [46]
3 years ago
10

Organic green seedless grapes cost $6.49 for 400 g. How much would 800 g cost? $ Hint Example I! Calc​

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
7 0

Answer:

800 g would cost $12.98

since 800 g is double 400 g just multiply 6.49 by 2.

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Tony paid 35% of the bill. Eric paid 3/8 of the bill. Jeff paid .175 of the bill and Gary paid 1/10 of the bill. Place the peopl
Blizzard [7]

Answer:

Eric,Tony,Jeff,Gary

Step-by-step explanation:

Given the payments made by each individual below:

  • Tony paid 35% of the bill.
  • Eric paid 3/8 of the bill.
  • Jeff paid 0.175 of the bill
  • Gary paid 1/10 of the bill.

The most convenient way to order their payments is to convert each to percentage.

Eric paid 3/8 of the bill.

  • In Percentage: \frac{3}{8}X100=37.5\%

Jeff paid 0.175 of the bill

  • In percentage, 0.175 X100 =17.5%

Gary paid 1/10 of the bill.

In Percentage: \frac{1}{10}X100=10\%

Therefore, the order from most to least is:

Eric(37.5%), Tony(35%),Jeff(17.5%),Gary(10%)

6 0
3 years ago
2 7/20 divided by 2/5 = ____
777dan777 [17]

Hi,

Solution:

Find Common Denominators,

2/5 = 8/20

2 7/20

Turn into improper fractions,

2 7/10 = 47/20

Divide,

47/20 ÷ 8/20 = 5.875/1 = 5 7/8

Answer,

5 7/8

8 0
3 years ago
(HELPP MEE PLEASE )THE ANSWER OPTIONS :<br> 2<br> 3<br> 4<br> 5
Ostrovityanka [42]

Answer:

the answer is 2

Step-by-step explanation:

8 0
3 years ago
What is the area of the segment?
SVEN [57.7K]

Answer:

28.54 ft²

Step-by-step explanation:

Area of segment = (\frac{\theta * \pi}{360} - \frac{sin(\theta)}{2}) * r^2

Where,

\theta = 90

r = 10 ft

Plug in the values

(\frac{90 * \pi}{360} - \frac{sin(90)}{2}) * 10^2

(0.7854 - 0.5) * 100

(0.2854) * 100

= 28.54 ft²

6 0
3 years ago
a landscaping company needs 160 gallons of 40% fertilize the shrubs in an office park. They have in stock 50% fertilizer and 30%
Novay_Z [31]

Let

x--------> volume of 50​% fertilizer

y--------> volume of 30% fertilizer

we know that

x+y=160-----> x=160-y-----> equation 1

x*0.5+y*0.3=160*0.4-----> equation 2

substitute equation 1 in equation 2

[160-y]*0.5+0.3*y=63.8----> 77-0.35*y+0.25*y=63.8

0.10*y=13.2------> y=13.2/0.10----> y=132 gal

x=220-y----> x=220-132----> x=88 gal

the answer is

88 gal of 50​% fertilizer

132 gal 30​% fertilizer

5 0
3 years ago
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