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navik [9.2K]
3 years ago
13

Assume that trees are subjected to different levels of carbon dioxide atmosphere with 7% of the trees in a minimal growth condit

ion at 370 parts per million (ppm), 10% at 440 ppm (slow growth), 49% at 550 ppm (moderate growth), and 34% at 670 ppm (rapid growth). What is the mean and standard deviation of the carbon dioxide atmosphere (in ppm) for these trees
Mathematics
1 answer:
taurus [48]3 years ago
3 0

Answer: The mean and standard deviation are 567.2 and 89.88 resp.

Step-by-step explanation:

Since we have given that

For 370 parts per million = 7% = 0.07

For 440 parts per million = 10% = 0.10

For 550 parts per million = 49% = 0.49

For 670 parts per million = 34% = 0.34

So, Mean of the carbon dioxide atmosphere for these trees would be

E[x]=370\times 0.07+440\times 0.1+550\times 0.49+670\times 0.34=567.2

And

E[x^2]=370^2\times 0.07+440^2\times 0.1+550^2\times 0.49+670^2\times 0.34=329794

So, Variance would be

Var\ x=E[x^2]-E[x]^2=329794-567.2^2=8078.16

So, the standard deviation would be

\sigma=\sqrt{8078.16}=89.88

Hence, the mean and standard deviation are 567.2 and 89.88 resp.

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Jodie spent 25% less buying her English reading books thank Claudia. .Gianna spent 9% less than Claudia. Gianna spent more than
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Answer:

21.3%

Step-by-step explanation:

Given that:

Money spent by Jodie for buying English reading books = 25% lesser than that of Claudia

and

Money spent by Gianna is 9% lesser than that of Claudia.

To find:

By what percent, Gianna spent more than Jodie ?

Solution:

Let the money spent by Claudia on her English books = 100

Now, as per question statement:

Money spent by Jodie = 100 - \frac{9}{100}\times 100 = 75

Money spent by Gianna = 100 - \frac{25}{100}\times 100 = 91

Now, to find the answer:

\dfrac{\text{Difference between money spent by Gianna and Jodie}}{\text{Money spent by Jodie}}\times 100

\Rightarrow \dfrac{91-75}{75}\times 100\\\Rightarrow \dfrac{16}{75}\times 100\\\Rightarrow \bold{21.3\%}

Therefore, Gianna spent <em>21.3% </em>more than the amount that was spent by Jodie.

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Step-by-step explanation:

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Eden just bought a trough in the shape of a rectangular prism for her horses. She needs to know what volume of water to add to t
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The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let w represent the width, hence:

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Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w

V(w) = w³ + 20w² - 429w

Rate of change = dV/dw = 3w² + 40w - 429

When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423

When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118

Rate = 10118 - 5423 = 4695 in³/in

The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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