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NARA [144]
3 years ago
13

What is the mass, in grams, of a piece of aluminum if its temperature changes from 25.0 ºC to 31.5 ºC when it absorbs 42.2 joule

s of energy? The specific heat for aluminum is 0.89J/gºC
Chemistry
1 answer:
Illusion [34]3 years ago
4 0

Answer:

m = 7.29 grams

Explanation:

Given that,

Initial temperature, T₁ = 25ºC

Final temperature, T₂ = 31.5ºC

The specific heat of the metal is 0.89 J/gºC.

We know that the heat released due to the change in temperature is given by :

Q=mc\Delta T\\\\m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{42.2 }{0.89\times (31.5-25)}\\\\m=7.29\ g

So, the mass of the piece is equal to 7.29 grams.

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2. HOW MUCH HEAT IS REQUIRED TO BE RELEASED WHEN
jarptica [38.1K]

Answer: -112200J

Explanation:

The amount of heat (Q) released from an heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = ?

Mass of water vapour = 30.0g

C = 187 J/ G°C

Φ = (Final temperature - Initial temperature)

= 100°C - 120°C = -20°C

Then apply the formula, Q = MCΦ

Q = 30.0g x 187 J/ G°C x -20°C

Q = -112200J (The negative sign does indicates that heat was released to the surroundings)

Thus, -112200 joules of heat is released when cooling the superheated vapour.

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4 years ago
PLEASE I NEED YOUR HELP, I WILL GIVE 10 POINTS PLEASEEEEE
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Answer:

Erosion

Explanation:

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The [OH-] of a solution is 7.89 10^-12 M. What is the pH of the solution? it acidic or basic? *
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Answer: pH = 2,897 , basic[H+][OH-] = 10^{-14} ==> [H+] = \frac{10^{-14}}{7,89*10^{-12} } =\frac{1}{789} \\pH= -lg([H+]) = 2,897 \\pH basic

Explanation:

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Correct name for #10 please
ira [324]

Answer:

CH₃CH(CH₃)CH(C₃H₇)CH₂CH(CH₃)₂:

4-isopropyl-2-methylpentane.

Explanation:

Step One: Draw the structure formula of this compound. Parentheses in the formula indicate substitute groups that are connected to the carbon atom to the left.

For example, the first (CH₃) indicates that the second carbon atom from the left is connected to:

  • the CH₃- on the left-hand side,
  • the -CH(C₃H₇)CH₂CH(CH₃)₂ on the right-hand side,
  • a hydrogen atom, and
  • an additional CH₃- group that replaced one hydrogen atom.

Each carbon atom in this compound is connected to four other atoms. All bonds between carbon atoms are single bonds.

The C₃H₇ in the second pair of parentheses is the condensed form of CH₃CH₂CH₂-. See the first sketch attached. Groups in parentheses are highlighted.

Step Two: Find the carbon backbone. The backbone of a hydrocarbon is the longest chain of carbon atoms that runs through the compound. See the second sketch attached. The backbone of this compound consists of seven carbon atoms and is highlighted in green. The name for this backbone shall be heptane.

Step Three: Identify and name the substitute groups.

The two substitute groups are circled in blue in the second sketch.

  • The one on the right -CH₃ is a methyl group.
  • The one on the left is branched. \begin{aligned}\text{CH}_3-&\text{CH}-\text{CH}_3\\[-0.5em]&\;|\end{aligned} This group can be formed by removing one hydrogen from the central carbon atom in propane. The name for this group is isopropyl.

Step Four: Number the atoms.

Isopropyl shall be placed before methyl. Start from the right end to minimize the index number on all substitute groups. The methyl group is on carbon number two and the isopropyl group on carbon number four. Hence the name:

4-isopropyl-2-methylheptane.

5 0
4 years ago
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