<h2><u>ANSWER </u>⇒ 80</h2><h2 /><h2><u>EXPLANATION </u>⇒ To solve this we can use <u>PEMDAS,</u> first subtract in the parentheses, than add, then finally you can subtract...</h2><h2><u>YOUR ANSWER SHOULD BE 80</u></h2>
<h3>I think this is right, but sorry if I am wrong.</h3><h2>
</h2><h2 /><h3 />
I believe the answer is A
This question may be trick question xD haha.
Anyways, a right triangle is a triangle with a right angle (90 degrees). In your picture, that triangle is a right triangle, but the sides could be a bit slanted. Please take a picture from top view, so I can see it properly.
The triangle's length does not matter in this case. As long as it has a right angle, it's a right triangle.
Answer:
Step-by-step explanation:
cot²(3x)=y
y²-3y+2=0
y²-y-2y+2=0
y(y-1)-2(y-1)=0
(y-1)(y-2)=0
y=1,y=2
cot3x=1
tan 3x=1=tan (π/4)=tan (nπ+π/4)
3x=nπ+π/4=(4nπ+π)/4=(4n+1)π/4
x=(4nπ+1)π/12,n is an integer.
cot 3x=2
tan 3x=1/2
3x=tan^{-1}(1/2)≈26.57°+360n
x≈8.86°+120n
Answer:
No, because the reflection of ABC is not congruent to A’B’C’.
Step-by-step explanation:
we know that
The rule of the reflection across the line y=x is equal to
(x,y) -------> (y,x)
so
A(-6,6) -------> A'(6,-6) ----> is ok
B(-3,3) ------> B'(3,-3) ----> is ok
C(-8,2) ------> C'(8,-2) ----> is not ok ( is not a reflection acros the line y=x)
therefore
The triangles are no t congruent, because the reflection of ABC is not congruent to A’B’C’
