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jok3333 [9.3K]
3 years ago
8

Sara’s even holds55 gallons of gas.the TVs fuel guage show that the tank is on quarter full.can Sara drive 100 miles before she

stops for gas?justirfy your reason
Mathematics
1 answer:
Eduardwww [97]3 years ago
4 0
There is no answer; not enough information. You don't know how many miles to the gallon the car makes.
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What is the answer to 0=- 1/4(16)+b
Setler79 [48]

Answer:

<h2>b = 4</h2>

Step-by-step explanation:

0=-\dfrac{1}{4\!\!\!\!\diagup_1}\cdot16\!\!\!\!\!\diagup^4+b\\\\0=-4+b\qquad\text{add 4 to both sides}\\\\4=-4+4+b\\\\4=b\to b=4

5 0
3 years ago
Select all expressions that are equivalent to 2x+2+4x-2x-5 **
Umnica [9.8K]
The answer that you’re looking for is B & D
6 0
3 years ago
Question 11 (5 points)
Semenov [28]

Hello :)

here you need to use the slope intercept formula to find your equation:

y= mx+b

b= the y- intercept

m= the slope

we are already given the slope and the x & y

y=-3x+(-2)

your answer would be a) y = -3x - 2

8 0
3 years ago
2x^{2} +4x+1=0 <br> Solve for x.
Viefleur [7K]
2x^2 + 4x + 1 = 0

2x^2 + 4x + 1 - 1 = 0 - 1

2x^2 + 4x = -1

X(2x + 4) = -1

X = -1.

2x + 4 = -1
2x + 4 - 4 = -1 - 4
2x = -5
2x/2 = -5/2
X = -5/2.

I believe these are the solutions. If not you can use the quadratic formula to solve for the roots, solutions.
7 0
3 years ago
Find S12 for geometric series: (-7.5) + 15 + (-30) + ...
kolezko [41]

Answer:

S12 for geometric series: (-7.5) + 15 + (-30) + ... would be: 10237.5

Step-by-step explanation:

Given the sequence to find the sum up-to 12 terms

(-7.5) + 15 + (-30) + ...

As we know that

A geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}

\frac{15}{\left(-7.5\right)}=-2,\:\quad \frac{\left(-30\right)}{15}=-2

\mathrm{The\:ratio\:of\:all\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

r=-2

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

a_1=\left(-7.5\right)

a_n=a_1\cdot r^{n-1}

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

a_n=\left(-7.5\right)\left(-2\right)^{n-1}

a_n=-\left(-2\right)^{n-1}\cdot \:7.5

\mathrm{Geometric\:sequence\:sum\:formula:}

a_1\frac{1-r^n}{1-r}

\mathrm{Plug\:in\:the\:values:}

n=12,\:\spacea_1=\left(-7.5\right),\:\spacer=-2

  =\left(-7.5\right)\frac{1-\left(-2\right)^{12}}{1-\left(-2\right)}

  =-7.5\cdot \frac{1-\left(-2\right)^{12}}{1+2}

\mathrm{Multiply\:fractions}:\quad \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}

  =-\frac{-30712.5}{1+2}          ∵  \left(1-\left(-2\right)^{12}\right)\cdot \:7.5=-30712.5

 =-\frac{-30712.5}{3}

 =\frac{30712.5}{3}

 =10237.5

Thus, S12 for geometric series: (-7.5) + 15 + (-30) + ... would be: 10237.5        

5 0
3 years ago
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