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MrMuchimi
2 years ago
6

Can someone please give me the answers I will mark you brilliant as soon as it pops up

Mathematics
2 answers:
Rom4ik [11]2 years ago
6 0
I believe 80 sorry if wrong
Vesna [10]2 years ago
5 0

Answer:

1.) =50x+30y

2.? The first one

Step-by-step explanation:

1.)\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac,  a=10,\:b=5x,\:c=3y

=10\cdot \:5x+10\cdot \:3y=50x+30y

2.) The first one

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tamaranim1 [39]
The total cost would be $82.80.
5 0
3 years ago
Read 2 more answers
How do you answer the picture below?
3241004551 [841]

Answer:

42cm²

Step-by-step explanation:

because if the perimeter of the rectangle is 28 then the length is 5, 5 - 11 = 6, the formula for finding the trapezium is to add the 2 parallel sides, half them, then times them with the length so your sum will look like this, 5+9=14, (i knew the other side was 9 as the length of AB is the same as the length of FC, which is the one of the parallel sides of the trapezium) then we do 14÷2=7, finally we times 7 by 6 which is 42cm²

3 0
3 years ago
Valerie is performing an experiment by spinning a metal weight around on the end of a nylon thread. How far does the metal weigh
Triss [41]

Answer:

35.6 m

Step-by-step explanation:

Number of revolutions = 40

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3 0
3 years ago
Do you flip the inequality sign, yes or no? Explain why –5x < 35
Ivahew [28]

Answer:

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4 0
3 years ago
One shape is approaching a poor from the east traveling west at 15 mph and its presently 3 miles east east of the port I second
valentinak56 [21]

Answer:

DL/dt = 17 mph

Step-by-step explanation:

The ships and the port shape a right triangle

Ship  going west ( x-direction)   is traveling at 15 mph

Ship going north  (y-direction) is traveling at 10 mph

The distance L between ships is:

L²  = x² + y²

Tacking derivatives on both sides of the equation with respect to time

we get

2*L*DL/dt = 2*x*Dx/dt  + 2*y*Dy/dt    (1)

In that equation we know:

Dx/dt  = 15 mph

Dy/dt  = 10 mph

At the moment  ship traveling from the east is at 3 miles from the port

then x = 3 m  and the other ship is at 4 miles north

then by Pythagoras theorem

L = √ 3² + 4²    L = 5

By substitution in equation 1

2*5*DL/dt  = 2*3*15 + 2*4*10

10* DL/dt  =  90  +  80

DL/dt = 170 / 10

DL/dt = 17 mph

4 0
3 years ago
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