Please answer this for 100 points. Also click on the picture to full screen it.

In 2018, Mike Krzyewski and John Calipari topped the list of highest paid college basketball coaches (Sports Illustrated website

expeople1 [14]

From the data given, we estimate the population mean and population standard deviation. Then, we use this estimate to find a 95% confidence interval for the population variance and the population standard deviation.

Sample:

Salaries in millions of dollars: 2.2, 1.5, 0.5, 1.3, 2.4, 1.5, 2.7, 0.3, 2.0, 0.3

Question a:

The mean is the sum of all values divided by the number of values. So

$\overline{x} = \frac{2.2 + 1.5 + 0.5 + 1.3 + 2.4 + 1.5 + 2.7 + 0.3 + 2.0 + 0.3}{10} = 1.42$

The sample mean salary is of 1.42 million.

Question b:

The standard deviation is the square root of the difference squared between each value and the mean, divided by one less than the number of values.

So

$s = \sqrt{\frac{(2.2-1.42)^2 + (1.5-1.42)^2 + (0.5-1.42)^2 + (1.3-1.42)^2 + (2.4-1.42)^2 + (1.5-1.42)^2 + (2.7-1.42)^2 + ...}{9}} = 0.8772$

Thus, the estimate for the population standard deviation is of 0.8772 million.

Question c:

The sample size is $n = 10$

The significance level is $\alpha = 1 - 0.05 = 0.95$

The estimate, which is the sample standard deviation, is of $s = 0.8772$ .

Now, we have to find the critical values for the Pearson distribution. They are:

$\chi^2_{\frac{\alpha}{2},n-1} = \chi^2_{0.025,9} = 19.0228$

$\chi^2_{1-\frac{\alpha}{2},n-1} = \chi^2_{0.975,9} = 2.7004$

The confidence interval for the population variance is:

$\frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2},n-1}} < \sigma^2 < \frac{(n-1)s^2}{\chi^2_{1-\frac{\alpha}{2},n-1}}$

$\frac{9*0.8772^2}{19.0228} < \sigma^2 < \frac{9*0.8772^2}{2.7004}$

$0.3641 < \sigma^2 < 2.5646$

Thus, the 95% confidence interval for the population variance is (0.3641, 2.5646)

Question d:

Standard deviation is the square root of variance, so:

$\sqrt{0.3641} = 0.6034$

$\sqrt{2.5646} = 1.6014$

The 95% confidence interval for the population standard deviation is (0.6034, 1.6014).

For more on confidence intervals for population mean/standard deviation, you can check brainly.com/question/13807706

4 0

3 years ago

Solve the following quadratic equation:<br> (3x – 5)2 = 4

Katarina [22]

Answer:

Step-by-step explanation:

It is mandatory (required) to use " ^ " for exponentiation:

(3x – 5)^2 = 4

Taking the square root of both sides, we get

3x - 5 = ±2, or

3x = 5 ±2, or

(a) 3x = 7 => x = 7/3, and

(b) 3x = 3, or x = 1

7 0

3 years ago

Directions

telo118 [61]

Answer:

Step-by-step explanation:

Directions

You cut a pizza cut into 2 equal slices and eat 1 slice, or 1/2

of the pizza. You cut another pizza of the same size cut into 4

equal slices, but you still only eat 1 slice. This time you've

eaten only 1/4 of the pizza, which is less than 1/2.

As you divide the pizza into more slices, the bottom number

(the denominator) gets bigger, but the size of each slice gets

smaller.

Drag the fractions in order from least to greatest.

1/3

1/4

1/2

1/8

-------------------

1/3 = 0.33

1/4 = 0.25

1/2 = 0.5

1/8 = 0.125

so

1/8

1/4

1/3

1/2

6 0

2 years ago

Read 2 more answers

Find the lengths, if needed round to the nearest tenth

Elis [28]

Answer:

Step-by-step explanation:

Triangle ABC is a right angle triangle that is made up of 2 right angle triangle.

To determine y, we would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

15² = y² + 12²

225 = y² + 144

y² = 225 - 144 = 81

y = √81 = 9

To determine z,

20² = z² + 12²

400 = z² + 144

z² = 400 - 144 = 256

z = √256 = 16

7 0

4 years ago

PLEASE HELP!!!!

Genrish500 [490]

I believe 3-4 ships took part in the battle

3 0

4 years ago