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VMariaS [17]
2 years ago
10

A runner ran of a 5 kilometer race in 21 minutes. They ran the entire race at a constant speed.

Mathematics
1 answer:
IgorLugansk [536]2 years ago
6 0

Answer:

4.2

Step-by-step explanation:

the kilometro is 5 and race is 21. 5÷21=4.2

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Can someone help me
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1)  (c)∠ G = 34°

2) (a)  x = 33°

3) (d) The perpendicular segments are  JM, KL, PQ AND NR.

Step-by-step explanation:

Here in the given questions:

1)  p II r

⇒ ∠ G  = 34°  (ALTERNATE EXTERIOR ANGLES)

Hence, the measure of  ∠ G = 34°

2) In the given triangle:

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or, x = 105° - 72° =   33°   , or x = 33°

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7 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%3D16t%5E2%2B32t" id="TexFormula1" title="f(x)=16t^2+32t" alt="f(x)=16t^2+32t" align="
Nataly_w [17]

Answer:

- time = 1second

- maximum height = 16m

Step-by-step explanation:

Given the height of a pumpkin t seconds after it is launched from a catapult modelled by the equation

f(t)=-16t²+32t... (1)

The pumpkin reaches its maximum height when the velocity is zero.

Velocity = {d(f(x)}/dt = -32t+32

Since v = 0m/s (at maximum height)

-32t+32 = 0

-32t = -32

t = -32/-32

t = 1sec

The pumpkin reaches its maximum height after 1second.

Maximum height of the pumpkin is gotten by substituting t = 1sec into equation (1)

f(1) = -16(1)²+32(1)

f(1) = -16+32

f(1) = 16m

The maximum height of the pumpkin is 16m

6 0
3 years ago
????????????????????????????
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It would be 12.5 square miles I would appreciate the Brainliest
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