Well take the bottom and in this case its 18 and 30 so 18 x 30 = 540 then you do the two 15's times 30 and thats 450 times the 2 is 900 so 540+900+216 = so thats 1656 m 2 :)))))))))))
Another effective strategy for helping students improve their mathematics performance is related to solving word problems. More specifically, it involves teaching students how to identify word problem types based on a given problem’s underlying structure, or schema. Before learning about this strategy, however, it is helpful to understand why many students struggle with word problems in the first place.
Difficulty with Word Problems
Most students, especially those with mathematics difficulties and disabilities, have trouble solving word problems. This is in large part because word problems require students to:
Here: (Aₓ, Ay) = (-3,-4), (Bₓ, By) = (-7,0), (Cₓ, Cy) = (-3, 4)
Now, Formula of area of triangle is:
area = [Aₓ(By - Cy) + Bₓ(Cy - Ay) + Cₓ(Ay - By)] / 2
Substitute the values in to the expression,
area = [-3(0-4) - 7(-4-(-4)) - 3(-4-0)] / 2
area = [-3(-4) -7(0) -3(-4)] / 2
area = [12-0+12] / 2
area = 24 / 2
area = 12
Final answer would be 12 units.
Hope this helps!
Answer:
Step-by-step explanation:
Simply plug in 10 for <em>n</em>
9(1/3)¹⁰⁻¹
9(1/3)⁹
9(1/19683)
9/19683
Answer:
10.35 is the closest to the perimeter of the window.
Step-by-step explanation:
hope it helps
