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Mathematics

1 answer:

musickatia [10]2 years ago

8 0

Answer:

Step-by-step explanation:

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3(r+2)+5(2-r) =-32 can someone tell em the answer to that please

Alex17521 [72]

Answer:

r = 24

Step-by-step explanation:

3(r+2)+5(2−r)=−32

Step 1: Simplify both sides of the equation.

3(r+2)+5(2−r)=−32

(3)(r)+(3)(2)+(5)(2)+(5)(−r)=−32(Distribute)

3r+6+10+−5r=−32

(3r+−5r)+(6+10)=−32(Combine Like Terms)

−2r+16=−32

Step 2: Subtract 16 from both sides.

−2r+16−16=−32−16

−2r=−48

Step 3: Divide both sides by -2.

−2r/-2 = -48/-2

r = 24

8 0

2 years ago

Read 2 more answers

Mark dropped an object from a bridge 400 feet above the ground level with an initial velocity of 0. He knows that the gravitatio

lisabon 2012 [21]

Answer:

The first listed equation is the correct equation to solve

The correct answer is: t = 5 seconds

Step-by-step explanation:

Let me mention first that there is an error in the statement that the gravitational pull of the Earth is 16 ft/s^2. It is in fact 32 ft/s^2, and the actual equation uses half of the acceleration multiplied by the square of the variable time, so it gives as final expression :

$y(t)=-16\,t^2+ 0 \,t +400$

and we want to find the value/s for "t" that make this equation equal zero (when it reaches the ground and the object just touches the ground. This makes the equation we want to solve:

$0=-16\,t^2+ 0 \,t +400\\16\,t^2+0\,t -400=0$