Answer:
r = 24
Step-by-step explanation:
3(r+2)+5(2−r)=−32
Step 1: Simplify both sides of the equation.
3(r+2)+5(2−r)=−32
(3)(r)+(3)(2)+(5)(2)+(5)(−r)=−32(Distribute)
3r+6+10+−5r=−32
(3r+−5r)+(6+10)=−32(Combine Like Terms)
−2r+16=−32
−2r+16=−32
Step 2: Subtract 16 from both sides.
−2r+16−16=−32−16
−2r=−48
Step 3: Divide both sides by -2.
−2r/-2 = -48/-2
r = 24
Answer:
The first listed equation is the correct equation to solve
The correct answer is: t = 5 seconds
Step-by-step explanation:
Let me mention first that there is an error in the statement that the gravitational pull of the Earth is 16 ft/s^2. It is in fact 32 ft/s^2, and the actual equation uses half of the acceleration multiplied by the square of the variable time, so it gives as final expression :

and we want to find the value/s for "t" that make this equation equal zero (when it reaches the ground and the object just touches the ground. This makes the equation we want to solve:

which solving for "t" becomes:

So we adopt the positive answer (positive time) since the negative value has no physical meaning for this problem.
That is: t = 5 seconds
Answer:
B
Step-by-step explanation:
below 0 is negative
so -15
I think this is the answer