Answer:
y = 2
Step-by-step explanation:
-2y + 1 = y-5
-2 - y = -5 - 1
-3y = -6
y = -6 ÷ -3
y = 2
Answer:
a=2.4
Step-by-step explanation:
Answer:
Slope intercept form: y = 4x + 14
Slope: 4
Y-intercept: 14
Step-by-step explanation:
y - 2 = 4(x + 3)
Use distributive property
y - 2 = 4x + 12
y - 2 + 2 = 4x + 12 + 2
y - 0 = 4x + 14
y = 4x + 14
Answer:
Answer: 216 cm2 (square centimetres
, in your question you had to put cm3, cubic centimetres, it's IMPORTANT )
Step-by-step explanation:
A perfect cube by definition has 3 equal dimensions, as an immediate rule: volume and total surface are equal, only the unit of measure changes (cubic for the volume, square for surface).
But let's calculate it anyway:
Volume = Edge * Edge * Edge = length * width * depth =
(remember: all edges are equal in this case)
so Edge = ![\sqrt[3]{Volume}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7BVolume%7D)
in your example Edge =
= 6cm
So the surface of one side is 6*6 = 36
There are 6 sides in total, so the total surface is 6*36 = 216 
Note: I call them "edges" but in case of a cube most say just "length"
Answer:
See Explanation
Step-by-step explanation:
The question has missing details. So, I'll solve using a general assumption.
Let one of the coordinates of the figure be

Let the scale factor be n
When dilated, the new figure is:


To return the image back to the original figure, the new scale factor mus be a reciprocal of the previous scale factor i.e. 
So:

Substitute n(x,y) for A';



Take for instance:

-- scale factor



To get A from A', using the analysis above

