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3 years ago

A stone of weight 1 N falls downwards. Its g.p.e. decreases by 100 J. How far has it fallen?

Physics

1 answer:

sattari [20]3 years ago

3 0

Answer:

h = 100 m

Explanation:

Given that,

The weight of a stone, W = 1 N

It falls downwards. Its gravitational potential energy decreases by 100 J.

We need to find how far it is fallen.

The gravitational potential energy of an object is given by :

E = mgh

h is from where it has fallen

$h=\dfrac{E}{mg}\\\\h=\dfrac{100}{1}\\\\h=100\ m$

So, it has fallen 100 m.

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What is the number of significant digits in the measurement 104.100 m?

Oksana_A [137]

Answer:

6 significant digits

Explanation:

Number of significant digits of a number are the number of digits that carry a relevant contribution to the measurement.

For the case above;

104.100

rule - all digits to the right of the decimal of any number equal or greater than 1 will count as a significant digit.

104.100 --- .100 ( the three digits counts)

And since the the digits to the left are none zero digits, so they all count as significant digits.

104.100 --- 104 ( the three digits counts)

The total number of significant digits,

Since all the digits of the number 104.100 will count as a significant digit.

The number of significant digits is equal to the number of digits in the number.

N = 6

6 significant digits

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AleksandrR [38]

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3 years ago

A parachutist with a camera, both descending at a speed of 10.8 m/s, releases that camera at an altitude of 50 m. In this proble

Vadim26 [7]

Answer:

The velocity of the camera is 33.11 m/s.

Explanation:

Given that,

Speed = 10.8 m/s

Altitude = 50 m

Suppose determine the velocity of the camera just before it hits the ground?

We need to calculate the velocity of the camera

Using equation of motion

$v^2=u^2+2gs$

Where, v = final velocity of camera

u = initial speed of camera

s = distance

Put the value into the formula

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$v=33.11\ m/s$

The direction will be downward so it is the negative velocity.

Hence, The velocity of the camera is 33.11 m/s.

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3 years ago

If you are pushing on a box with a force of 20 N and there is a 7 N force on the box due to sliding friction, what is the net fo

vovangra [49]

Answer:

13 N

Explanation:

The Net Force of an object should be the difference between the forces applied to the object if the object is not in equilibrium. This object is not in equilibrium so therefore by finding the difference between the forces, you will find your answer. 20 N - 7 N = 13 N.

6 0

3 years ago

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