Sin2(x) +cos(x)=1
from the relation: (sin2(x) +cos2(x) =1 )
so , sin2(x)=1-cos2(x)
by subs. in the main eqn.
1-cos2(x) + cos(x) =1
by simplify the eqn.
cos(x) -cos2(x)=0
take cos(x) as a common factor
cos(x)* (1-cos(x))=0
then cos(x)=0 && cos(x)=1
cos(x)=0 if x= pi/2
& cos(x) = 1 if x = 0 , 2*pi
so the solution is x= {0,pi/2 , 2*pi}
Answer:
slope
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Since m is the coefficient of the x- term, then
The coefficient of the x- term gives the slope
What do you need help with? There is no picture or anything so...
Answer:
Step-by-step explanation:
There is missing information in the task: HD║FG !!!!!
∠HDE ≅ ∠FGE and ∠EHD ≅ ∠EFG
<u><em>ΔEHG ~ ΔEFG</em></u> (AAA theorem of similarity)
m∠F = 22°
m∠G = 89°
The answer is 1.
Rise over run :)
