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sdas [7]
3 years ago
10

Grace purchased a shirt and a pair

Mathematics
1 answer:
elixir [45]3 years ago
4 0

just subtract the total from the price of the shirt and boom thats the answer

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The table shows a pattern of exponents.<br><br> What is the pattern as the exponents decrease?
Marrrta [24]

Answer:

Option C is correct.

Step-by-step explanation:

We need to find the pattern as the exponent decreases.

the first value in the table is 125.

if we divide 125 by 5 i.e 125/5 we get 25

the next value in the table is 25

if we divide 25 by 5 i.e 25/5 we get 5

the next value in the table is 5

if we divide 5 by 5 i.e 5/5 we get 1

the next value in the table is 1

if we divide 1 by 5 i.e 1/5 we get 1/5

the next value in the table is 1/5

if we divide 1/5 by 5 i.e 1/5*5 we get 1/25

the next value in the table is 1/25

So, the pattern is if we divide the previous value by 5 we get the next value in the table.

So, Option C is correct.

5 0
3 years ago
Read 2 more answers
Find the range of the data. scores: 84, 83, 80, 95, 99, 95, 83, 83, 92, 84
In-s [12.5K]
To find the range of these scores, we must take the largest scores and subtract the smallest from it.

The largest score is 99, and the smallest score is 80.

99 - 80 = 19

3 0
3 years ago
Read 2 more answers
-7 &lt; 3x + 2 &lt; 5.<br> Solve for x
yarga [219]

Answer:

-3 < x < 1, This is the domain

5 0
3 years ago
Hey guys stuck on three questions, can you help out a bit? Thanks!
alexandr1967 [171]

Answer:

D

Step-by-step explanation:

Because the numbers do not comply with the like 11+6+18+21= no answer and multiplying them all didn't matter either so its none of the above

7 0
3 years ago
Please help me find limit​
cluponka [151]

9514 1404 393

Answer:

  -13/11

Step-by-step explanation:

Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...

  \displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}

4 0
3 years ago
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