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3 years ago

28) Solve the inequality: 12x−10>170

Mathematics

1 answer:

suter [353]3 years ago

4 0

Answer:

p=5x+3y

solve for x, number of cupcakes. isolate x

5x=p-3y

divide by 5

x=(p-3y)/5

Step-by-step explanation:

D. x<15

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6 students want lemonade and 12 students

Ksenya-84 [330]

Answer:

2:1

Step-by-step explanation:

well we show ratio by the sign ' : '

ratio of iced tea to lemonade= 12:6

now we reduce it to minimum by dividing it with same number.

12 is divisible by 6

so,

the reduced form is = 2:1

therefore,

ratio of the number of students who want iced tea to the number of students who want lemonade = 2:1.

5 0

3 years ago

I'm trying to help my friend

diamong [38]

4a^b3^7c^3

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3 years ago

Solve the following exponential equations. 10^(x+1) − 10^(x−1) = 1287

Rudiy27

Answer:x=2.114

Step-by-step explanation:

Given

$10^{x+1}-10^{x-1}=1287$

$10\times 10^x-\frac{10^x}{10}=1287$

Let $10^x=y$

$10y-\frac{y}{10}=1287$

$\frac{100y-y}{10}=1287$

$99y=1287\times 10$

$y=\frac{12870}{99}=130$

$10^x=130$

Taking $\log$ both sides

$x\log (10)=\log (130)$

$x=\frac{\log (130)}{1}$

$x=2.114$

7 0

3 years ago

A room contains three urns: u1, u2, u3. u1 contains 3 red and 2 yellow marbles. u2 contains 3 red and 7 yellow marbles. u3 conta

Archy [21]

Answer:

$\dfrac{11}{30}$

Step-by-step explanation:

Urn U1: 3 red and 2 yellow marbles, in total 5 marbles.

The probability to select red marble is $\dfrac{3}{5}=0.6.$

Urn U2: 3 red and 7 yellow marbles, in total 10 marbles.

The probability to select red marble is $\dfrac{3}{10}=0.3.$

Urn U1: 1 red and 4 yellow marbles, in total 5 marbles.

The probability to select red marble is $\dfrac{1}{5}=0.2.$

The probability to choose each urn is the same and is equal to $\frac{1}{3}.$

Thus, the probability that the marble is red is

$\dfrac{1}{3}\cdot 0.6+\dfrac{1}{3}\cdot 0.3+\dfrac{1}{3}\cdot 0.2=\dfrac{1.1}{3}=\dfrac{11}{30}.$

4 0

3 years ago

I need help.. 1. 4(7p+8) 2.-7(2+8s) 3.-8(-6d+3)

Advocard [28]

1. 28p + 32

2. - 56s - 14

3. 48d - 24

#thanks for the points!

#Chloe919 

#carry on learning

8 0

3 years ago