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Digiron [165]
3 years ago
5

In Art Class, you designed a rectangle stained glass window. The

Mathematics
1 answer:
Ierofanga [76]3 years ago
4 0

Answer:

Step-by-step explanation:

Draw a triangle and label the sides (picture below):

● the length is 2x+2

● and the width or the height is 6x

The perimeter of a rectangle is the sum of the sides

● P = 2x+2 + 6x + 2x+2 + 6x

Isolate the similar terms

● P = (2x+2x+6x+6x) + (2+2)

● P = 16x + 4

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How to find R of a cone?
bonufazy [111]
Multiply the volume by 3.
Multiply the height by π, which is a numeric constant that begins 3.14 and never terminates.
<span>Divide the tripled volume by the product of the height and π.
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3 years ago
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Find the sum. I need help.​
Artyom0805 [142]

Answer:

B

Step-by-step explanation:

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3 years ago
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A researcher is conducting a study of charitable donations by surveying a simple random sample of households in a certain city.
nirvana33 [79]

Answer:

H0: p ≤ 0.50

Ha: p > 0.50

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

For the case above;

Let p represent the proportion of households in the city that gave a charitable donation in the past year

The null hypothesis is that the proportion of households in the city that gave a charitable donation in the past year is not more that 0.50

H0: p ≤ 0.50

The alternative hypothesis is that the proportion of households in the city that gave a charitable donation in the past year is more that 0.50

Ha: p > 0.50

7 0
3 years ago
A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft
lakkis [162]

\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}

\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}

\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}

8 0
3 years ago
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