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elena-s [515]
3 years ago
11

Twice a number added to a smaller number is 5. The difference of 5 times the smaller number and the larger number is 3. Let x re

present the smaller number and y represent the larger number.
Which equations represent the situation?

A: 2Y+x=5
5x-y=3

B: 2x+y=5
5y-X= 3

C: 2y + x = 5
y-5x = 3

D: 2x+y-5
X-5y = 3​
Mathematics
1 answer:
Veronika [31]3 years ago
3 0

Answer:

The equations which represents the situation are

1) 2Y+X=5

2) 5X-Y=3

Step-by-step explanation:

<em>~Cornasha_Weeb</em>

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The value of the length DF is 17

<h3>How to determine the length DF?</h3>

The statement Triangle ABC = Triangle ADF means that the triangles ABC and ADF are congruent triangles.

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What is the most common factor between 139 and 100
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1

Step-by-step explanation:

The common factors are:

1

The Greatest Common Factor:

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Answer:

P(X>400)=P(\frac{X-\mu}{\sigma}>\frac{400-\mu}{\sigma})=P(Z>\frac{400-440}{20})=P(z>-2)

And we can find this probability using the complement rule:

P(z>-2)=1-P(z

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(z>-2)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(440,20)  

Where \mu=440 and \sigma=20

We are interested on this probability

P(X>440)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>400)=P(\frac{X-\mu}{\sigma}>\frac{400-\mu}{\sigma})=P(Z>\frac{400-440}{20})=P(z>-2)

And we can find this probability using the complement rule:

P(z>-2)=1-P(z

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(z>-2)=1-P(z

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