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2 years ago

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Mathematics

1 answer:

Brums [2.3K]2 years ago

4 0

Answer:

Option 5

Step-by-step explanation:

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Find the domain of the following piecewise function. [-4,3) (-4,3] [-4,6) (-4,6]

aniked [119]

The answer is [-4,6)
Graph both the you can easily find the answer

6 0

3 years ago

The diagram shows a semi circle inside a rectangle of length 140m. the semi circle touches the rectangle at P, Q and R. Calculat

exis [7]

Answer: 250m

Step-by-step explanation:

Length of rectangle = 140m

Length of rectangle = diameter of semicircle = 140m

Therefore, Radius(r) = 140m / 2 = 70m

Perimeter of the shaded region:

Length of tangent at P + length of tangent at Q + shaded portion of arc(AB)

Length of tangent = diameter / 2

Length of tangent = 70m

Perimeter of a circle = 2πr = 2 × 22/7 × 70 = 440m

shaded portion = 440 / 4 = 110m

Therefore, perimeter of shaded portion equals

70m + 70m + 110m = 250m

4 0

3 years ago

Three people who work full-time are to work together on a project, but their total time on the project is to be equivalent to th

arlik [135]

1/6 of their time has to be put in to the project.

7 0

3 years ago

A community bird-watching society makes and sells simple bird feeders to raise money for its conservation activities. The materi

valentina_108 [34]

Answer:

N(x) = 40 - 2x

P(x) = -2x² + 52 x - 240

maximum profit = 13

Step-by-step explanation:

given data

feeder cost = $6

average sell = 20 per week

price = $10 each

solution

we consider here price per feeder = x

and profit per feeder id here formula = x - 6

so that here

total profit will be

P (x) = ( x - 6 ) Nx

here N(x) is number of feeders sold at price = x

so formula for N (x) is here

N(x) = 20 - 2 ( x - 10 )

N(x) = 40 - 2x

so that

P(x) = (x-6) ( 40 - 2x)

P(x) = -2x² + 52 x - 240

since here

a = -2

b = 52

c = -240

a < 0

so quadratic function have maximum value of c - $\frac{b^2}{4a}$

so it will be

maximum value = -240 - $\frac{52^2}{4(-2)}$

maximum value = 98

so here maximum profit attained at

x = $\frac{-b}{2a}$

x = $\frac{-52}{2(-2)}$

x = 13

maximum profit = 13

3 0

3 years ago

A ladder is leaning up against a house. The ladder is 20 feet long and the base of the ladder is 12 feet away from the house. Ho

MrRa [10]

Answer:

16 feet

Step-by-step explanation:

The length of the ladder=20 feet

Distance from the base of the ladder to the house = 12 feet

You will notice that a wall is vertical and the ladder makes an angle with the horizontal ground(making it the hypotenuse). This is a right triangle problem.

To find the how far up the house can the ladder can reach, we simply find the third side of the right triangle.

From Pythagoras theorem

$Hyp^2=Opp^2+Adj^2\\20^2=12^2+Adj^2\\Adj^2=400-144\\Adj^2=256\\Adj=\sqrt{256}=16$

The third side of the right triangle is 16. Therefore the ladder leans 16 feet from the ground.

8 0

3 years ago

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