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2 years ago

A 5-pound bag of cat food costs $11.25.What is the unit price of the cat food indollars per pound?

Mathematics

2 answers:

Kipish [7]2 years ago

8 0

Answer:

2.25 dollars per pound

Step-by-step explanation:

Take the cost and divide by the number of pounds

11.25 dollars / 5 pounds

2.25 dollars per pound

Lerok [7]2 years ago

6 0

Answer:

The cat food costs 2.25 dollars per pound

Step-by-step explanation:

First let's write this like an equation. Let's add a variable instead of pounds and you can name that anything you like. I prefer to use X. And since we have 5 pounds of cat food, we put 5x.

X = 1 Pound of cat food

11.25$ = 5x

Now we want X alone, so we divide both sides by 5

11.25$/5 = 5x/5

Now if we divide we get

2.25$ = X

And if we turn x back into pounds of cat food, we get that, for 2 dollars and 25 cents we have 1 bag of cat food

2.25$ = 1 Pound of cat food

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A towel has a repeating pattern of two green stripes, then 3 blue stripes, and then 1 yellow stripe. If the towel has 20 stripes

EleoNora [17]

The answer would be a total of 9 blue stripes.

4 0

3 years ago

If 30 buses can carry 1,500 people, how many people can 5 buses carry? A 200 © 500 B 250 D 750

maksim [4K]

Answer:

$\boxed {\boxed {\sf 250 \ people}}$

Step-by-step explanation:

Let's set up a proportion using the following setup.

$\frac {buses}{people}=\frac {buses}{people}$

We know 30 buses can carry 1,500 people.

$\frac {30 \ buses}{1500 \ people}=\frac {buses}{people}$

We don't know how many people 5 buses can carry, so we say 5 buses carry x people.

$\frac {30 \ buses}{1500 \ people}=\frac {5 \ buses}{x \ people}$

$\frac {30 }{1500 }=\frac {5 }{x }$

Cross multiply. Multiply the numerator of the first fraction by the second fraction's denominator. Then, multiply the first denominator by the second numerator.

$30*x=1500*5\\30x=7500$

Solve for x. It is being multiplied by 30. The inverse of multiplication is division. Divide both sides by 30.

$30x/30=7500\\x=250$

5 buses can carry 250 people.

7 0

2 years ago

What is Rational Number

abruzzese [7]

Rational number, in arithmetic, a number that can be represented as the quotient p/q of two integers such that q ≠ 0. In addition to all the fractions, the set of rational numbers includes all the integers, each of which can be written as a quotient with the integer as the numerator and 1 as the denominator.

8 0

1 year ago

Read 2 more answers

A) If the 5th term of an A.P. is double the 7th term, show that the sum of the 17 terms zero.

gayaneshka [121]

Answer:

see explanation

Step-by-step explanation:

The nth term of an AP is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₅ is double a₇ , then

a₁ + 4d = 2(a₁ + 6d) , that is

a₁ + 4d = 2a₁ + 12d ( subtract a₁ from both sides )

4d = a₁ + 12d ( subtract 12d from both sides )

- 8d = a₁

The sum of n terms of an AP is

$S_{n}$ = $\frac{n}{2}$ [ 2a₁ + (n - 1)d ] , substitute values

$S_{17}$ = $\frac{17}{2}$ ( 2(- 8d) + 16d)

= 8.5(- 16d + 16d)

= 8.5 × 0

= 0

5 0

2 years ago

You are at a stall at a fair where you have to throw a ball at a target. There are two versions of the game. In the first

Tomtit [17]

Answer:

$P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729$

And the probability of loss with the first wersion is 0.729

$P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774$

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Alternative 1

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=3, p=0.1)$