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Anarel [89]
2 years ago
9

Using trig to solve for missing angle

Mathematics
1 answer:
sasho [114]2 years ago
3 0

here's the answer to your question

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Gideon is painting all sides of a square pyramid-shaped decoration at the top of his fence post. A net of the decoration is show
frez [133]
Gideon is painting all sides thus we find the overall area of the square pyramid given in the picture. A square pyramid is a polyhedron that consists of a square and 4 triangles. To solve the area that Gideon will have to paint, we can calculate the area of the square and the area of the triangles then add these two values of area. We proceed as follows:
Area of the square = s^2 where s is the measure of the side
Area of the square = 4^2 = 16 in^2

Area of the triangle= 1/2 bh where b is the base of the triangle and h is height of the triangle
Area of the triangle = 1/2 (4) (5) = 10 in^2
We multiply the area of the triangle to four in order to obtain the total area of the triangles.
Total area of the triangles = 4 x 10 = 40 in^2

We then add the two areas,
Total Area = 16 + 40 = 56 in^2

Thus the total area that Gideon will have to paint for one square pyramid is 56 in^2.
6 0
3 years ago
Approximately 85% of persons age 70 to 84 live in their own household and are income-qualified for home purchases.
miv72 [106K]

Answer:

The probability that exactly two of the four live in their own household and are income-qualified is  = .0975

Step-by-step explanation:

Given -

Approximately 85% of persons age 70 to 84 live in their own household and are income-qualified for home purchases.

Probability of sucess ( p ) = 85% =.85

Probability of failure ( q ) = 1 - .85 =.15

n = 4

From combination of n events taking r sucess we use binomial distribution

P(X = r) = \binom{n}{r}p^{r}q^{n-r}

where , r = 2

the probability that exactly two of the four live in their own household and are income-qualified is =

P(X = 2) = \binom{4}{2}0.85^{2}0.15^{4 - 2}

                = \frac{4!}{(2!)(2!)} \times 0.7225  \times .0225

                 = 6 \times 0.7225  \times .0225

                 = .0975

4 0
3 years ago
What is the leading coefficient in 1-2x+5x^4 when in standard form
Vera_Pavlovna [14]
That's a lot of points for this question. You don't have to offer that much. 

Leading Coefficient: When written in standard form (starting with the variable with the highest power, going to the variable with the next highest power ... all the way down to a number with no variable), the leading coefficient is the number in front of the variable with the highest power. 

Let me put this less technically. Find the variable with the highest power. The number in front of that variable is the leading coefficient.

Write this in standard form. 5x^4 -2x + 1
The number in front of the x^4 is the answer.
5 <<<<< answer 
4 0
3 years ago
PU 15 cm<br> 0<br> 162<br> 1. Find the arc length of PQR.
Ad libitum [116K]
It isn’t really clear to me it’s confusing
4 0
3 years ago
Find the volume of the prism below
myrzilka [38]
The volume of the prism is 40 because 5 x 8 =40
7 0
3 years ago
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