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3 years ago

Why do windows of distant houses appear to reflect the sun only when rising or setting

2 answers:

4 0

Because the sun in the middle of the day, is up above and the windows are lower on the side. When the sun is setting or rising the sun is closer in a way and lower to the windows than before. So the raise of the sun hits more.
I don’t actually know the answer, I just thought of it and think it’s a good answer.

alisha [4.7K]3 years ago

3 0

<span> most importantly, the sun is reflected back at the same angle as the angle of incidence, so with vertical panes of glass and the sun overhead, the reflection will just hit the ground before traveling any distance. </span>

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If an engine can produce 670 J of energy in 1 min, how many watts can it output?

daser333 [38]

Answer:

11.2Watts

Explanation:

Given parameters:

Energy produced by the engine = 670J

Time taken = 1min = 60s

Unknown:

Number of watts it can output = ?

Solution:

This problem entails finding the power of the engine.

Power is the rate at which work is being done.

So;

Power = $\frac{Work done }{time}$

Power = $\frac{670}{60}$ = 11.2Watts

6 0

3 years ago

Two large rectangular aluminum plates of area 180 cm2 face each other with a separation of 3 mm between them. The plates are cha

lbvjy [14]

Answer:

Electric flux;

Φ = 30.095 × 10⁴ N.m²/C

Explanation:

We are given;

Charge on plate; q = 17 µC = 17 × 10^(-6) C

Area of the plates; A_p = 180 cm² = 180 × 10^(-4) m²

Angle between the normal of the area and electric field; θ = 4°

Radius;r = 3 cm = 3 × 10^(-2) m = 0.03 m

Permittivity of free space;ε_o = 8.85 × 10^(-12) C²/N.m²

The charge density on the plate is given by the formula;

σ = q/A_p

Thus;

σ = (17 × 10^(-6))/(180 × 10^(-4))

σ = 0.944 × 10^(-3) C/m²

Also, the electric field is given by the formula;

E = σ/ε_o

E = (0.944 × 10^(-3))/(8.85 × 10^(-12))

E = 1.067 × 10^(8) N/C

Now, the formula for electric flux for uniform electric field is given as;

Φ = EAcos θ

Where A = πr² = π × 0.03² = 9π × 10^(-4) m²

Thus;

Φ = 1.067 × 10^(8) × 9π × 10^(-4) × cos 4

Φ = 30.095 × 10⁴ N.m²/C

3 0

3 years ago

A rock thrown with speed 7.50 m/s and launch angle 30.0 ∘ (above the horizontal) travels a horizontal distance of d = 18.0 m bef

Iteru [2.4K]

Answer:

height from where rock was thrown is 27.916 m

Explanation:

speed = 7.50 m/s

θ = 30°

g= 9.8 m/s²

horizontal distance = 18 m

time require for vertical displacement

$time = \frac{distance}{velocity} \\t = \frac{18}{7.5\ cos30^0}$

t = 2.8 sec

now for calculation of height

s = ut + 0.5 a t²

-h = v sinθ× t + 0.5 ×(-9.8)× (2.8²)

-h = 7.5 sin30°× 2.8 - 0.5 ×(9.8)× (2.8²)

-h = -27.916 m

h= 27.916 m

height from where rock was thrown is 27.916 m

5 0

3 years ago

Select the order in which the flow of current is listed from greatest to the least.

Radda [10]

Answer:

Short circuit, closed circuit, open circuit

7 0

3 years ago

Read 2 more answers

Which of the following represents a case in which you are not accelerating? View Available Hint(s) Which of the following repres

padilas [110]

Answer:

4) Driving in a straight line at 60 miles per hour

Explanation:

1) Driving 60 miles per hour around a curve

2) Going from 0 to 60 miles per hour in 10 seconds

3) Slamming on the brakes to come to a stop at a stop sign

4) Driving in a straight line at 60 miles per hour

1) The speed is constant here, but in circular motion you have an acceleration that is v^2/r, where v is the speed and r the radius

2) You are accelerating from 0 to 60

3) You are desaccelerating

4) constant speed , no acceleration

8 0

3 years ago