Answer:
V = 6.65 [volt]
Explanation:
First, we must calculate the power by means of the following equation, where the voltage is related to the energy produced or consumed in a given time.
Using the power we can calculate the voltage, by means of the following equation that relates the voltage to the current.
where:
V = voltage [Volts]
I = current = 200 [mA] = 0.2 [A]
Answer:
0.1575 m/s^2
Explanation:
Solution:-
- Acceleration ( a ) is expressed as the rate of change of velocity ( v ).
- We are given that the trains starts from rest i.e the initial velocity ( vo ) is equal to 0. Then the train travels from reference point ( so = 0 ) to ( sf = 5.6 km ) from the reference.
- During the travel the train accelerated uniformly to a speed of ( vf =42 m/s ).
- We will employ the use of 3rd kinematic equation of motion valid for constant acceleration ( a ) as follows:
- We will plug in the given parameters in the equation of motion given above:
Answer: the acceleration during the first 5.6 km of travel is 0.1575 m / s^2