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3 years ago

5

An astronaut is using a drill to fix the gyroscopes on the Hubble telescope. Suddenly she loses her footing and floats away from

the telescope. She should throw the drill in the direction opposite the telescope to give herself what? In the direction of the telescope

1 answer:

Naddik [55]3 years ago

8 0

The direction the telescope may be heading ummm honestly I don’t know the answer to that

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Drew observed in an experiment that algae in a nearby lake could be found at six meters below the water's surface on a clear day

babymother [125]

In this question the options are missing; here are the options:

What was the dependent variable in Drew's experiment?

A. The depth at which the algae were found

B. The sky conditions on a particular day

C. The amount of algae measured

D. The lake that was being observed

The answer to this question A. The depth at which the algae were found

Explanation:

In an experiment, it is common there are at least two factors or variables. Additionally, the variable that is modified by others or that depend on others is always the dependent variable.

In the case of the experiment presented, there are two main factors: sky conditions and depth at which algae can be found. From these, the dependent factor is the depth because this depth changes with the sky condition or depends on the sky conditions. Also, the dependent variable is always the factor being studied, for example, in this case, Drew's focus is to study how the location of algae in terms of depth changes.

8 0

3 years ago

If it takes a planet 2.8 Ã— 108 s to orbit a star with a mass of 6.2 Ã— 1030 kg, what is the average distance between the planet

Shtirlitz [24]

The average distance between the planet and the star is:

R=9.36*10^11 m

Orbital velocity v=√{(G*M)/R},

G = gravitational constant =6.67*10^-11 m³ kg⁻¹ s⁻²,

M = mass of the star

R =distance from the planet to the star.

v=ωR, with ω as the angular velocity and R the radius

ωR=√{(G*M)/R},

ω=2π/T,

T = orbital period of the planet

To get R we write the formula by making R the subject of the equation

(2π/T)*R=√{(G*M)/R}

{(2π/T)*R}²=[√{(G*M)/R}]²,

(4π²/T²)*R²=(G*M)/R,

(4π²/T²)*R³=G*M,

R³=(G*M*T²)/4π²,

R=∛{(G*M*T²)/4π²},

Substitute values

R=9.36*10^11 m

As was already said, Earth is located roughly 150 million kilometres (93 million miles) from the Sun on average. It is 1 AU. Mars is on our fictitious football field's three-yard line. On average, the distance between the Sun and the red planet is around 142 million miles (228 million kilometres).

Learn more about average distance:

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The complete question is ''If it takes a planet 2.8 × 108 s to orbit a star with a mass of 6.2 × 10^30 kg, what is the average distance between the planet and the star? 1.43 × 10^9 m 9.36 × 10^11 m 5.42 × 10^13 m 9.06 × 10^17 m''.

4 0

1 year ago

Two objects attract each other gravitationally. If the distance between their centers decreases by a factor of 2, how does the g

kramer

Answer:

The gravitational force between them increases by a factor of 4

Explanation:

Gravitational force is a force of attraction between two objects with masses M and m which are separated by a distance R. It is given mathematically as:

Fg = GMm/R²

Where G = Gravitational constant.

If the distance between their centers, R, decreases by a factor of 2, then it means the new distance between their centers is:

r = R/2

Hence,the gravitational force becomes:

Fg = GMm/r²

Fg = GMm/(R/2)²

Fg = GMm/(R²/4)

Fg = 4GMm/R²

Hence,the gravitational force increases by a factor of 4.

6 0

3 years ago

why did scientists using classical, newtonian physics have difficulty explaining the photoelectric effect

zzz [600]

The correct answer is :

According to classical electrodynamics, light energy is a wave that is absorbed by atoms in a manner similar to how an object absorbs radiant heat. So, the atoms of a metal would absorb more energy the brighter the light was. It would be feasible for an electron in a metal to break free from its atoms if it received enough energy from the incoming wave. The more energy absorbed, the more energetic the metal's released electrons would be. Additionally, no electrons could conceivably be ejected until each atom had enough light energy. Light intensity was far more important than light frequency.

In many respects, the photo-electric effect contradicted this strategy:

If the light was below a specific frequency, no matter how bright it was, no electrons were released. Increased light intensity increased the number of electrons that were released, but not their energy, if the light was above this frequency.
Regardless of how weak the light was, electrons were nearly immediately emitted from the metal.
Even though the intensity of the light was reduced, an increase in its frequency led to more energising electrons leaving the metal.

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7 0

1 year ago

While standing outdoors one evening, you are exposed to the following four types of electromagnetic radiation: yellow light from

Alona [7]

Answer: FM radio waves, AM radio waves, yellow light, micro waves

Explanation:

5 0

3 years ago

Read 2 more answers