The second one I beileve is the answer to your question
This problem can be solved by manipulating the formula for power, which is: P = VI. Where:
P = Power in watts
V= Voltage in volts
I = Current in amperes
Since we are already given the power and voltage, simple substitution can be done.
P = VI
3.5 watts = 120 volts * I
I = 3.5 / 120
I = 0.0292 Amperes or 29.2 milliAmperes
Therefore, the current through the bulb is 29.2mA
Answer:
-6
Step-by-step explanation:
You have to multiple -2 by 15 and -8 separately
8 - 2(15-8)
8 -30 + 16
24-30 = -6
Here are your examples
A spring that is bouncing up and down.
An atom or molecule that resonates with a certain frequency.
In fact, anything that resonates: a violin string, a pendulum, the air column in a muffler,.....
I would be able to help but I need it to be in English
