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WINSTONCH [101]
3 years ago
6

A potter's wheel moves uniformly from rest to an angular speed of 0.17 rev/s in 32.0 s.

Physics
1 answer:
uranmaximum [27]3 years ago
6 0

Answer:

a)   α = 0.0334 rad / s² ,  b) w = 2.14  rad/s see that the angular velocity doubles.

Explanation:

This is a magular kinematics exercise

Let's reduce the magnitudes to the SI system

   w = 0.17 rev /s (2π rad / 1rev) = 1.07 rad / s

a) as part of rest its initial velocity is zero w or = 0

        w = w₀ + α t

        α = \frac{\omega -\omega_{o} }{t}

        α = \frac{1.07-0}{32}

         α = 0.0334 rad / s²

b) If we double the angular relation what will be the final velocity

       w = w₀ + (2α) t

       w = 0 + 2 0.0334 32

       w = 2.14  rad/s

We see that the angular velocity doubles.

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Answer:

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Using binomial theorem in the above eqn:

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Answer:

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