Question

A potter's wheel moves uniformly from rest to an angular speed of 0.17 rev/s in 32.0 s.

Answer 1

Answer:

a)   α = 0.0334 rad / s² ,  b) w = 2.14  rad/s see that the angular velocity doubles.

Explanation:

This is a magular kinematics exercise

Let's reduce the magnitudes to the SI system

   w = 0.17 rev /s (2π rad / 1rev) = 1.07 rad / s

a) as part of rest its initial velocity is zero w or = 0

        w = w₀ + α t

        α = $\frac{\omega -\omega_{o} }{t}$

        α = $\frac{1.07-0}{32}$

         α = 0.0334 rad / s²

b) If we double the angular relation what will be the final velocity

       w = w₀ + (2α) t

       w = 0 + 2 0.0334 32

       w = 2.14  rad/s

We see that the angular velocity doubles.