Answer:
238 kg/s
Explanation:
We are given;
Instantaneous Thrust; T = 7.26 × 10^(5) N
Exhaust speed; V_t = 3.05 × 10^(3) m/s
Now, the formula for the instantaneous thrust is given by;
T = V_t × ΔM/Δt
Since we are looking for mass of fuel the engine burns per second, then;
ΔM/Δt = T/V_t
Where ΔM/Δt is the mass of fuel burned per second.
Thus;
ΔM/Δt = (7.26 × 10^(5))/(3.05 × 10^(3))
ΔM/Δt ≈ 238 kg/s
Momentum P is given by:
Given: m₁ = 62 kg, m₂ = 78.1 kg, v₁ = ?, v₂ = 0 m/s, v₁₊₂ = 1.29 m/s
before:
after:
Since momentum is conserved, the momentum before the collision must be equal to the momentum after the collision.
Solve for v₁.
Answer:
the initial velocity of the ball is 104.67 m/s.
Explanation:
Given;
angle of projection, θ = 60⁰
time of flight, T = 18.5 s
let the initial velocity of the ball, = u
The time of flight is given as;
Therefore, the initial velocity of the ball is 104.67 m/s.
Explanation:
Metals get charged by induction ,the charges are transferred from the electroscope causing earthing: Charges on the electroscope induce opposite charges on the conductor.
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