Question

An airtight box has a removable lid of area 1.10 10-2 m2 and negligible weight. The box is taken up a mountain where the air pressure outside the box is 7.00 104 Pa. The inside of the box is completely evacuated. What is the magnitude of the force required to pull the lid off the box

Answer 1

Answer:

F=$7.7\times10^2 N$

Explanation:

The magnitude of force required to pull the lid off the box by air pressure.

We know that Pressure, P= Force(F)/Area(A)

Force, F= P×A

Given: A=$1.10\times10^{-2} m^2$

P=$7\times10^{4} Pa$.

Therefore, F=$7\times10^{4}\times1.10\times10^{-2}$.

F=$7.7\times10^2 N$