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3 years ago

7

Every object that has mass attracts every other object with a gravitational force: It has been proven that the size of the

2 answers:

sergejj [24]3 years ago

8 0

Answer;

- This statement about matter and its behavior is best classified as a Law.
-It is the Law of Universal Gravitation.

Explanation;
-The Law of Universal Gravitation states that every point mass attracts every other point mass in the universe by a force pointing in a straight line between the centers-of-mass of both points, and this force is proportional to the masses of the objects and inversely proportional to their separation.This attractive force always points inward, from one point to the other.
-The Law applies to all objects with masses, big or small. Two big objects can be considered as point-like masses, if the distance between them is very large compared to their sizes or if they are spherically symmetric.

denpristay [2]3 years ago

7 0

Answer:

this is a law because it is a constant fact of nature

Explanation:

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What is static friction?

givi [52]

Answer:

Plzzzzzzzzzzzzzzzz brainliest

Explanation:

In static friction, the frictional force resists force that is applied to an object, and the object remains at rest until the force of static friction is overcome. In kinetic friction, the frictional force resists the motion of an object. ... The frictional force itself is directed oppositely to the motion of the object.

7 0

2 years ago

Two particles, one with charge -5.45 × 10^-6 C and one with charge 4.39 × 10^-6 C, are 0.0209 meters apart. What is the magnitud

Levart [38]

Explanation:

Given that,

Charge 1, $q_1=-5.45\times 10^{-6}\ C$

Charge 2, $q_2=4.39\times 10^{-6}\ C$

Distance between charges, r = 0.0209 m

1. The electric force is given by :

$F=k\dfrac{q_1q_2}{r^2}$

$F=9\times 10^9\times \dfrac{-5.45\times 10^{-6}\times 4.39\times 10^{-6}}{(0.0209)^2}$

F = -492.95 N

2. Distance between two identical charges, $r=0.0209\ m$

Electric force is given by :

$F=\dfrac{kq_3^2}{r^2}$

$q_3=\sqrt{\dfrac{Fr^2}{k}}$

$q_3=\sqrt{\dfrac{492.95\times (0.0209)^2}{9\times 10^9}}$

$q_3=4.89\times 10^{-6}\ C$

Hence, this is the required solution.

3 0

3 years ago

To fill the medication prescription, what information must the pharmacy technician need to obtain? A. The name of the medication

shepuryov [24]

C. Patient info, name of med, dosage & route, special instructions, prescriber’s DEA#, and number of refills

3 0

3 years ago

An assault rifle fires an eight-shot burst in 0.40 s. Each bullet has a mass of 7.5 g and a speed of 300 m/s as it leaves the gu

myrzilka [38]

Answer:

The average recoil force on the gun during that 0.40 s burst is 45 N.

Explanation:

Mass of each bullet, m = 7.5 g = 0.0075 kg

Speed of the bullet, v = 300 m/s

Time, t = 0.4 s

The change in momentum of an object is equal to impulse delivered. So,

$F\times t=mv\\\\F=\dfrac{mv}{t}$

For 8 shot burst, average recoil force on the gun is :

$F=\dfrac{8mv}{t}\\\\F=\dfrac{7.5}{1000}\cdot\dfrac{300}{0.4}\cdot8\\\\F=45\ N$

So, the average recoil force on the gun during that 0.40 s burst is 45 N.

5 0

3 years ago

Flashlight has resistance of 2.4 what voltage is applied by the batteries if the current is 2.5a

Sergeeva-Olga [200]

Answer:

6 voltage is applied by the batteries.

Explanation:

To solve this sort of problem involving current, resistance and voltage, we use the relation:<em> </em><em>Voltage</em><em>= </em><em>Current x Resistance</em>.

From the problem, the following have been given:

Resistance= 2.4 ohms.

Current= 2.5 amps.

Required: Voltage?

Fix the values of current and resistance into the relation:

Voltage= <em>2.5 x 2.4</em>

=6 volts.

5 0

3 years ago