.875 .88 .98
7/8, 9/9, .98 is your answer from least to greatest!
Answer:
1
Step-by-step explanation:
By order of operations, we first evaluate the parentheses, which is 2 * 1 = 2. We then evaluate the brackets, which are 3 / 2 =
. Finally,
*
=
or 1.
Area=legnth times width
so multiply them together use distributive property
a(b+c)=ab+ac so
in this problem
(a+b)(c+d+e)=(a+b)(c)+(a+b)(d)+(a+b)(e)
so
x^2-2 times (2x^2-x+2)=(x^2)(2x^2-x+2)-(2)(2x^2-x+2)=(2x^4-x^3+2x^2)-(4x^2-2x+4)
add like terms
2x^4-x^3+(2x^2-4x^2)-2x+4
2x^4-x^3-2x^2-2x+4
C = 10d+ 45 ? Hope this helps? Let me know if it’s right or not.
The law of cosines for this particular situation is b^2 = a^2 + c^2 - 2ac cosB.
Filling in what you know, you have b^2 = 25 + 49 - [2(5)(7)-.1908], which simplifies to b^2 = 74 - 69.8092 which gives you a b^2 value of 4.1908, but you have to take the square root of that so you get a side value for b of 2.05.