WHAT are the highest frequency and the lowest frequency pets of the EM spectrum?
1 answer:
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Answer: the index of refraction of material X will be 1.09 and the angle the light makes with the normal in the air is 81.25°.
Explanation: To find the answer, we need to know the Snell's law.
<h3>What is Snell's law of refraction? Using this, how to solve the problem?</h3>- The Snell's law for refraction can be written as,
where, i is the incident angle, r is the refracted angle, n is the refractive index.
- As we know that the refractive index of water is 1.33
- For the first case, incident angle from the picture is 65°, and the refracted angle is 48°. Thus, the refractive index of the medium X will be,
- In the second case, incident angle is 48° and we have to find the refracted angle r for the air.
- As we know that the refractive index of air is 1.
- Thus, the refracted angle will be,
Thus, we can conclude that, the index of refraction of material X will be 1.09 and the angle the light makes with the normal in the air is 81.25°.
Learn more about the Snell's law here:
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Q = magnitude of charge at each of the three locations A, B and C = 2 x 10⁻⁶ C
r₁ = distance of charge at origin from charge at B = 50 - 0 = 50 cm = 0.50 m
r₂ = distance of charge at origin from charge at C = 100 - 0 = 100 cm = 1 m
F₁ = magnitude of force by charge at B on charge at origin
F₂ = magnitude of force by charge at C on charge at origin
Magnitude of force by charge at B on charge at origin
inserting the values
F₁ = 0.144 N
Magnitude of force by charge at C on charge at origin
inserting the values
F₂ = 0.036 N
Net force on the charge at the origin is given as
F = F₁ + F₂
F = 0.144 + 0.036
F = 0.18 N
from the diagram , direction of net force is towards left or negative x-direction.
