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Kipish [7]
4 years ago
10

WHAT are the highest frequency and the lowest frequency pets of the EM spectrum?

Physics
1 answer:
Rus_ich [418]4 years ago
8 0
Highest frequency EM waves: cosmic rays and gama rays

Lowest frequency EM waves:
Radio and Tv waves
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A balloon is a sphere with a radius of 5.0 m. the force of air against the walls of the balloon is 45 n. what is the air pressur
Mazyrski [523]

The air pressure inside the balloon is: 0.1432 Pa

The formulas and procedures that we will use to solve this problem are:

  • a = 4 * π * r²
  • P = F/a

Where:

  • a = area of the sphere
  • r = radius
  • π = mathematical constant
  • P = Pressure
  • F = Force
  • a = surface area

Information about the problem:

  • r = 5.0 m
  • F = 45 N
  • 1 Pa = N/m²
  • 1 N = kg * m/s²
  • a=?
  • P=?

Using the formula of the sphere area we get:

a = 4 * π * r²

a = 4 * 3.1416 * (5.0 m)²

a = 314.16 m²

Applying the pressure formula we get:

P = F/a

P = 45 N/314.16 m²

P = 0.1432 Pa

<h3>What is pressure?</h3>

It is a physical quantity that expresses the force applied on the area of a surface.

Learn more about pressure at: brainly.com/question/26269477

#SPJ4

7 0
1 year ago
find the gravitational force this shell exerts on a 1.60 kg point mass placed at the distance 5.01 m from the center of the shel
RideAnS [48]

The gravitational force of the shell exerts is 4.25m x 10¯¹² N.

We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses of objects. The magnitude of gravitational force can be determined as

F = G.m1.m2 / R²

where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.

From the question above, we know that

m1 = 1.6 kg

m2 = m

R = 5.01 m

By substituting the following parameters, we get

F = G.m1.m2 / R²

F = 6.674 × 10¯¹¹  . 1.6 . m / 5.01²

F = 4.25m x 10¯¹² N

where m is the mass of the shell

For more on gravitational force at: brainly.com/question/19050897

#SPJ4

7 0
1 year ago
Important nuclei of the indirect (multineuronal) system that receive impulses from the equilibrium apparatus of the inner ear an
Lera25 [3.4K]

Answer:

B. Vestibular nuclei

Explanation:

The nerve information generated by the vestibular receptors travels through the vestibular portion of the eighth pair that penetrates the brain stem at the level of the brain stem bridge. At this level there are four vestibular nuclei, which receive the synapses of these axons, coming from the ridges and macules. The semicircular ducts predominantly terminate in the superior and medial nuclei. While the fibers coming from the macules end on the lateral, medial and inferior nuclei. Some fibers of the eighth pair end in the flocculonodular lobe of the cerebellum, <u>these connections play an important role in controlling posture and balance.</u>

From the vestibular nuclei, two bundles of fibers descending to the spinal cord originate from the medial and lateral vestibular spinal bundles and a bundle of fiber that rises in the brain stem that participates in the coordination of eye movements, the medial longitudinal fascicle, which participates in Rotational nystagmus This system also participates in an important way in the control of some ocular movements by the fibers that it contributes to the medial longitudinal fascicle, which is a structure that interconnects the motor nuclei of the extrinsic muscles of the eyeballs VI or abdicens nucleus (abductor) on one side and IV or pathetic nucleus (trochlear) and III or nucleus of the common ocular motor (oculomotor) on the opposite side.

6 0
3 years ago
A hockey puck is sliding across a frozen pond with an initial speed of 9.5 m/s. It comes to rest after sliding a distance of 37.
Bond [772]

Answer:

<h3>The coefficient of kinetic friction between the puck and the ice is \mu _{k} = 0.12</h3>

Explanation:

Given :

Initial speed  v_{o} = 9.5 \frac{m}{s}

Displacement x = 37.4 m

From the kinematics equation,

  v^{2} - v^{2} _{o}  = 2ax

Where v^{2}   = final velocity, in our example it is zero (v =0), a = acceleration.

   a =- \frac{90.25}{ 2 \times 37.4}

   a =- 1.21 \frac{m}{s^{2} }

From the formula of friction,

  F =- \mu _{k } N

Minus sign represent friction is oppose the motion

Where N = mg ( normal reaction force )

 ma = -\mu _{k}  m g                                                  ( ∵ g = 9.8 \frac{m}{s^{2} } )

So coefficient of friction,

 \mu_{k} = \frac{1.21}{9.8}

 \mu_{k} = 0.12

Therefore, the coefficient of kinetic friction between the puck and the ice is  \mu _{k} = 0.12 .

4 0
3 years ago
If your car tachometer says your engine is moving at 1200 RPM, then what is it's angular velocity in Rad/sec?
Ostrovityanka [42]

Answer:

125.66 R/s

Explanation:

First    1200  r / min = 20 r/sec

20 r/s  *  2pi Radians / r = 40 pi Radians / sec = 125.66 R/s

3 0
2 years ago
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