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Morgarella [4.7K]

3 years ago

14

A parallel-plate capacitor has a charge Q and plates of area A. What force acts on one plate to attract it toward the other plat

e? Because the electric field between the plates is E 5 Q /Ae0, you might think the force is F 5 QE 5 Q2/Ae0. This conclusion is wrong because the field E includes contributions from both plates, and the field created by the positive plate cannot exert any force on the positive plate. Show that the force exerted on each plate is actually F 5 Q2/2Ae0. Suggestion: Let C 5 e0A/x for an arbitrary plate separation x and note that the work done in separating the two charged plates is W 5 e F dx.

1 answer:

Setler79 [48]3 years ago

8 0

Answer:

$F=\dfrac{Q^2x}{2\varepsilon _0A}$

Explanation:

Given that

Charge = Q

Area =A

Electric filed =E

We know that

$F=\dfrac{dU}{dx}$

U=Energy

We know that energy in capacitor given as

$U=\dfrac{Q^2}{2C}$

$C=\dfrac{\varepsilon _oA}{x}$

$U=\dfrac{Q^2x}{2\varepsilon _0A}$

So

Force F

$F=\dfrac{Q^2x}{2\varepsilon _0A}$

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3 years ago

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netineya [11]

Answer:

The coefficient of static friction between the puppy and the floor is 0.7273.

Explanation:

The horizontal force applied to move the puppy from a steady state has to be greater than the force of static friction, after it is moving the force needs to be equal to be greater than the force of dynamic friction in order to maintain its movement. The force of static friction is given by:

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Where $F_s$ is the static friction force, $\mu_s$ is the coefficient of static friction and $N$ is the normal force. Since there's no angle on the flor the normal force is equal to the weight of the puppy, therefore, $N = 110\text{ N}$ , to make the puppy moving we need to use a force of 80 N, therefore, $F_s = 80 \text{ N}$ , so we can solve for the coefficient as shown below:

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The coefficient of static friction between the puppy and the floor is 0.7273.

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4 years ago

The planet Krypton has a mass of 8.8 × 1023 kg and radius of 2.5 × 106 m. What is the acceleration of an object in free fall nea

djverab [1.8K]

Answer:

Acceleration, $a=9.39\ m/s^2$

Explanation:

Given that,

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Value of gravitational constant, $G=6.6726\times 10^{-11}\ Nm^2/kg^2$

To find,

The acceleration of an object in free fall near the surface of Krypton.

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4 years ago

If the temperature of a gas is increased by 10x, what will happen to the volume?

xxMikexx [17]

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The volume of a fixed mass of gas is directly proportional to its temperature provided the pressure of the gas is kept constant.

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8 0

2 years ago

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Answer:

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3 years ago