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max2010maxim [7]
3 years ago
15

A top in the form of a cone is spinning about its symmetry axis at a rate �, while precessing about the vertical axis at a rate

�. Assume that the nutation angle � is constant. Assume that the moments of inertia of the top about the symmetric and the transverse axes are given by Is and It respectively about the center of mass C. a) Given that the floor on which the top is precessing is smooth, find a relationship between the spin rate and the precession rate. [30] b) How does the answer change if you were told now that the floor had friction, and the top was precessing with its vertex O fixed?

Physics
1 answer:
fredd [130]3 years ago
7 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

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Existing rocks can become sedimentary rocks when they are subjected to which conditions?
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The radiation per unit area from the Sun reaching the earth is 1400 W/m2 , approximately the amount of radiative power per unit
natka813 [3]

Answer:

83.2 W/m^2

Explanation:

The radiation per unit area of a star is directly proportional to the power emitted, which is given by Stefan-Boltzmann law:

P=\sigma A T^4

where

\sigma is the Stefan-Boltzmann constant

A is the surface area

T is the surface temperature

So, we see that the radiation per unit area is proportional to the fourth power of the temperature:

I \propto T^4

So in our problem we can write:

I_1 : T_1^4 = I_2 : T_2^4

where

I_1 = 1400 W/m^2 is the power per unit area of the present sun

T_1 = 5800 K is the temperature of the sun

I_2 is the power per unit area of sun X

T_2 = 2864 K is the temperature of sun X

Solving for I2, we find

I_2 = \frac{I_1 T_2^4}{T_1^4}=\frac{(1400 W/m^2)(2864 K)^4}{(5800 K)^4}=83.2 W/m^2

6 0
3 years ago
Periodic trends vary as we move across the periodic table. In general, as you move across a row in the periodic table A) ionic s
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<span>In general, as you move across a row in the periodic table, B. atomic radius decreases.
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Read 2 more answers
Please help. I don’t understand this
skad [1K]

The short answer is that the displacement is equal tothe area under the curve in the velocity-time graph. The region under the curve in the first 4.0 s is a triangle with height 10.0 m/s and length 4.0 s, so its area - and hence the displacement - is

1/2 • (10.0 m/s) • (4.0 s) = 20.00 m

Another way to derive this: since velocity is linear over the first 4.0 s, that means acceleration is constant. Recall that average velocity is defined as

<em>v</em> (ave) = ∆<em>x</em> / ∆<em>t</em>

and under constant acceleration,

<em>v</em> (ave) = (<em>v</em> (final) + <em>v</em> (initial)) / 2

According to the plot, with ∆<em>t</em> = 4.0 s, we have <em>v</em> (initial) = 0 and <em>v</em> (final) = 10.0 m/s, so

∆<em>x</em> / (4.0 s) = (10.0 m/s) / 2

∆<em>x</em> = ((4.0 s) • (10.0 m/s)) / 2

∆<em>x</em> = 20.00 m

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2 years ago
What do Oxygen and Fluorine do to do Copper?
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It corrodes the copper by oxydation
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