A top in the form of a cone is spinning about its symmetry axis at a rate �, while precessing about the vertical axis at a rate
�. Assume that the nutation angle � is constant. Assume that the moments of inertia of the top about the symmetric and the transverse axes are given by Is and It respectively about the center of mass C. a) Given that the floor on which the top is precessing is smooth, find a relationship between the spin rate and the precession rate. [30] b) How does the answer change if you were told now that the floor had friction, and the top was precessing with its vertex O fixed?
1 answer:
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Total weight in tons
- 1ton=1000kg
Answer:
The question is incomplete. However, I believe, it is asking for the acceleration of the elevator. This is 3.16 m/s².
Explanation:
By Hooke's law,
F is the force on a spring, k is the spring constant and e is the extension or compression.
From the question,
This is the force on the mass suspended on the spring. Its acceleration, a, is given by
This acceleration is more than the acceleration due to gravity, g = 9.8 m/s². Hence the elevator must be moving up with an acceleration of
12.96 - 9.8 m/s² = 3.16 m/s²