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2 years ago

8

Help meh, no links and please give the right answer.

1 answer:

Schach [20]2 years ago

3 0

The length of the object

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Which action will decrease the gravitational force between two objects?

WITCHER [35]

Answer:

It’s D

Explanation:

6 0

2 years ago

A negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are

Irina-Kira [14]

If the comb and the paper are attracted to each other the charge on the paper, is D)must be positive

<h3>Laws of electrical attraction</h3>

This states that

Like charges attract
Unlike charges repel

Now, given that a negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are attracted to each other the charge on the paper, this implies that both the negatively charged plastic comb and the paper have opposite charges.

Since the charge on the plastic comb is negative, this means that the charge on the paper must be positive

So, if the comb and the paper are attracted to each other the charge on the paper, is D)must be positive

Learn more about electric charge here:

brainly.com/question/2373424

4 0

1 year ago

Find the total electric charge of 2.5 kg of electrons. Express your answer using two significant figures.

zimovet [89]

Answer : The total electric charge of electrons is, $-4.4\times 10^{11}C$

Explanation:

Answer : The number of electrons transferred are, $4.68\times 10^{20}$

Explanation :

First we have to calculate the number of electrons.

Number of electrons = $\frac{\text{Total mass of electrons}}{\text{Mass of one electron}}$

Mass of 1 electron = $9.1\times 10^{-31}kg$

Total mass of electron = 2.5 kg

Number of electrons = $\frac{2.5kg}{9.1\times 10^{-31}kg}$

Number of electrons = $2.75\times 10^{30}$

Now we have to calculate the total electric charge of electrons.

Formula used :

$Q=ne\\\\n=\frac{Q}{e}$

where,

n = number of electrons transferred = $2.75\times 10^{30}$

Q = charge on electrons = ?

e = charge on 1 electron = $-1.602\times 10^{-19}C$

Now put all the given values in the above formula, we get:

$2.75\times 10^{30}=\frac{Q}{-1.602\times 10^{-19}C}$

$Q=-4.4\times 10^{11}C$

Thus, the total electric charge of electrons is, $-4.4\times 10^{11}C$

4 0

3 years ago

Which of the following games below involves different manipulative skills like throwing and rolling and some motor skills?

seropon [69]

Answer:

striking and fielding

Explanation:

striking and fielding

4 0

3 years ago

What is the net displacement of the particle between 0 seconds and 80seconds?

Ira Lisetskai [31]

Answer:

Option (A)

Explanation:

Displacement of a particle on a velocity time graph is represented by the area between the line representing velocity and x-axis (time).

Displacement of a particle from t = 0 o t = 40 seconds = Area of ΔAOB

Area of triangle AOB = $\frac{1}{2}(\text{Base})(\text{height})$

= $\frac{1}{2}(40)(4)$

= 80 m

Similarly, displacement of the particle from t = 40 to t = 80 seconds = Area of ΔBCD

Area of ΔBCD = $\frac{1}{2}(40)(4)$

= 80 m

Total displacement of the particle from t = 0 to t = 80 seconds,

= 80 + 80

= 160 m

Option (A) will be the answer.

7 0

2 years ago