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iren [92.7K]
2 years ago
8

Help meh, no links and please give the right answer.

Physics
1 answer:
Schach [20]2 years ago
3 0

The length of the object

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What is meant by the statement that a laser beam is coherent, mono-chromatic and parallel?
Artyom0805 [142]

Answer:

Laser light however contains only one wavelength. This property makes lasers monochromatic, meaning of one color. Another property of lasers is that all the wavelengths are in phase, meaning they wave together. This property is called coherency. Laser light travels in the same direction, parallel to one another.

8 0
3 years ago
What is the dimensional formula of torque and force ​
ch4aika [34]

✿━━━━@♥ℳg━━━━✿

<h2>\boxed{Explained\:Answer}</h2>

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Torque = Force X Displacement

= MLT-2 X L = [M1L2T-2]

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6 0
2 years ago
Read 2 more answers
The leg's force forward on the foot= 500N
Anna11 [10]

There's so much going on here, in a short period of time.

<u>Before the kick</u>, as the foot swings toward the ball . . .

-- The net force on the ball is zero.  That's why it just lays there and
does not accelerate in any direction.

-- The net force on the foot is 500N, originating in the leg, causing it to
accelerate toward the ball.


<u>During the kick</u> ... the 0.1 second or so that the foot is in contact with the ball ...

-- The net force on the ball is 500N.  That's what makes it accelerate from
just laying there to taking off on a high arc.

-- The net force on the foot is zero ... 500N from the leg, pointing forward,
and 500N as the reaction force from the ball, pointing backward. 

That's how the leg's speed remains constant ... creating a dent in the ball
until the ball accelerates to match the speed of the foot, and then drawing
out of the dent, as the ball accelerates to exceed the speed of the foot and
draw away from it.


5 0
3 years ago
Compared to microwaves, ultraviolet waves have ___________________________ frequency.
vampirchik [111]
I think its a higher frequency
4 0
3 years ago
.prove : s=ut +½ at²​
o-na [289]

Explanation:

Let the distance covered by the body be s, initial and final velocities be u and v respectively and time taken be t.

\therefore Average\: velocity = \frac{u+v}{2} \\\\Now, \:we \:know\: that\\\\Distance \:covered\\ = Average\: velocity \times time\\\\\therefore s= \frac{(u+v) }{2} \times t..... (1)\\\\

By first equation of motion:

v = u + at

Substituting the value of v in equation (1), we find:

s= \frac{(u+u + at)}{2} \times t\\\\\therefore s= \frac{(2u + at)}{2} \times t\\\\\therefore s= \frac{(2ut + at^2)}{2}\\\\\therefore s=  \frac{2ut} {2}+ \frac{at^2}{2}\\\\   \huge \orange {\boxed {\therefore s= ut+ \frac{1}{2}at^2}} \\\\

Hence proved.

6 0
3 years ago
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