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3 years ago

How people get along with one another is called

Physics

1 answer:

Orlov [11]3 years ago

5 0

I am not sure what kind of answer you are looking for but the start of friendship.

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(m = 4.0 kg) the cockroach rides on the rim (at radius R) of a disk (M = 6.0 kg) that turns about its center like a merry-go-rou

kvasek [131]

Answer:

ω' = 2.5 rad/s

Explanation:

mass of cockroach, m = 4 kg

mass of disk, M = 6 kg

Radius of disc= R

initial angular velocity, ω = 2 rad/s

Let the final angular velocity is ω'

As no external torque is applied, so the angular momentum is constant.

Angular momentum = Moment of inertia x angular velocity

I ω = I' ω'

$\frac{1}{2}\left ( M+m \right )R^{2}\times {2} = \left (\frac{1}{2}MR^{2}+m(0.5R)^{2}) \right )\omega '$

$10R^{2} = 4R^{2}\omega '$

ω' = 2.5 rad/s

5 0

4 years ago

Is it possible for an atom to lose a proton and have a negative charge?<br> explain

denis-greek [22]

Answer:

Sometimes atoms gain or lose electrons. The atom then loses or gains a "negative" charge. These atoms are then called ions. Positive Ion - Occurs when an atom loses an electron negative charge it has more protons than electrons.

Explanation:

5 0

3 years ago

A satellite is spinning at 0.01 rev/s. The moment of inertia of the satellite about the spin axis is 2000 kg · m2. Paired thrust

enyata [817]

Answer:

Explanation:

Angular velocity of satellite

= 2π x .01

= .02 π rad /s

Initial angular momentum

Moment of inertia x angular velocity

= 2000 x .02 π

= 125.6 unit

Linear impulse produced by each thruster

= 15 N.s

Angular impulse

= 15 x 1.5 = 22.5 unit

Total angular impulse in 30 pulses

= 22.5 x 2 x 30

1350

This angular impulse will add total angular momentum of

1350 unit

So total angular momentum after 30 pulses

= 1350 + 22.5

= 1372.5 unit

So final angular velocity

= final angular momentum / moment of inertia

= 1372.5 / 2000

= 0 .686 rad /s

3 0

3 years ago

A runner taking part in the 200-m dash must run around the end of a track that has a circular arc with a radius of curvature of

Leto [7]

Answer: $2.27\ m/s^2$

Explanation:

Given

Length of the race track $L=200\ m$

the radius of curvature of the track $r=29.5\ m$

time taken to run on track is $t=24.4\ s$

Speed of runner is

$\Rightarrow v=\dfrac{L}{t}=\dfrac{200}{24.4}\\\\\Rightarrow v=8.196\ m/s$

Centripetal acceleration is

$\Rightarrow a_c=\dfrac{v^2}{r}=\dfrac{8.196^2}{29.5}\\\\\Rightarrow a_c=2.27\ m/s^2$

5 0

3 years ago

Two identical blocks are attached to the same massless rope, which is strung around two massless, frictionless pulleys. A massle

Alik [6]

Answer:

The value of mass 1, m1= 6/5m

The value of mass 2, m2= 3/5m

Explanation:

case 1:

here tension and the acceleration will be:

for m1;

mg-T=ma
2mg - 2T = 2ma .....1.

for m2:

2T-mg = ma/2 ..... 2.

adding the both equations,

2mg - 2T + 2T-mg = 2ma + ma/2

a = 2/5 g

putting the value of a into the equation 1.

mg - T = m* (2/5)g

T = 3/5 ( mg )

now

case 2:

The two identical blocks are released from the rest, the tension remains the same as the case 1.

so,

for m1:

2T-m2g=0

for m2:

2m2g - 2T =0

adding both equations we get,

2T-m2g + 2m2g - 2T = 0

m2 = m1 / 2

T = m1*g / 2

here we know that

T (case1) = T (case2)

3/5 ( mg ) = m1*g / 2

m1 = 6/5 m

hence

m2 = 3/5 m

learn more about tension here:

<u>brainly.com/question/23590078</u>

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4 0

2 years ago