F(x) = 2x + 1 when x <= -5
Now -10 is less than -5 so we plug x = -10 into 2x +1:-

f(-10) = 2(-10) + 1 = -19 answer

Now f(x) = x^2 when -5< x < 5
x =2 is within this range so f(2) = 2^2 = 4 answer

You can calculate the other 3 values by a similar method

5 0

2 years ago

Solve 5x + x − 3x > −12

Svetllana [295]

X>-4 would be the correct answer

5 0

2 years ago

Use calculus to find the largest possible area for a rectangular field that can be enclosed with a fence that is 500 meters long

rewona [7]

Let $x$ and $y$ be the sides of the rectangle. The perimeter is given to be 500m, so we are maximizing the area function $A(x,y)=xy$ subject to the constraint $2x+2y=500$ .

From the constraint, we find

$2x+2y=500\implies x+y=250\implies y=250-x$

so we can write the area function independently of $y$ :

$A(x,y)=\hat A(x)=x(250-x)=250x-x^2$

Differentiating and setting equal to zero, we find one critical point:

$\dfrac{\mathrm d\hat A(x)}{\mathrm dx}=250-2x=0\implies x=125$

which means $y=250-125=125$ , so in fact the largest area is achieved with a square fence that surrounds an area of $A(125,125)=125^2=15625\text{ m}^2$ .

7 0

2 years ago