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emmasim [6.3K]
2 years ago
15

Jodie ran at an average speed of 8 km/h for 45 minutes. How far did she run in km?

Mathematics
1 answer:
kenny6666 [7]2 years ago
5 0

Answer:

6 km.

Step-by-step explanation:

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For a certain horse race comma the odds in favor of a certain horse finishing in second placehorse race, the odds in favor of a
NikAS [45]

Answer:

0.33

Step-by-step explanation:

Let A denote an event. The odds of the horse finishing second is 33 to 67.

From the information, the total outcomes of event A is:

Total \ Outcomes, A=Favorable +Unfavorable\\\\=33+67\\\\=100

Hence, there are 100 total outcomes. The probability of the horse finishing second is calculated as:

p=\frac{n(A_f)}{n(A_u)}\\\\\\=p=\frac{33}{100}\\\\=0.33

Hence, the probability of finishing second is 0.33

7 0
3 years ago
Find the perimeter. Simplify your answer.
andrew-mc [135]

Answer:

3a+ 16

Hope this helps!

7 0
3 years ago
4. Two more than a certain number is 15 less<br> 7<br> 8<br> than the product of and the number.
Serggg [28]

<u>Answer</u><u>:</u>

Equation: x + 2 = 7/8x - 15

Solution: x = -136

<u>Explanation</u><u>:</u>

x + 2 = 7/8x - 15

2 + 15 = 7/8x - x

17 = 7/8x - 8/8x

17 = -1/8x

17 × -8 = x

-136 = x

4 0
3 years ago
I need help with this
Fudgin [204]
You can’t solve this, not enough information
5 0
3 years ago
Country Financial, a financial services company, uses surveys of adults age and older to determine if personal financial fitness
Yakvenalex [24]

Complete Question

Country financials, a financial services company, uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time. In February 2012, a sample of 1000 adults showed 410 indicating that their financial security was more that fair. In Feb 2010, a sample of 900 adults showed 315 indicating that their financial security was more than fair.

a

State the hypotheses that can be used to test for a significant difference between the population proportions for the two years.

b

What is the sample proportion indicating that their  financial security was more that fair in 2012?In 2010?

c

Conduct the hypothesis test and compute the p-value.At a .05 level of significance what is your conclusion?

Answer:

a

The null hypothesis is  H_o :  p_1 = p_2

The  alternative hypothesis is   H_a :  p_1  \ne  p_2

b

in 2012  \r  p_1  =0.41

in 2010  \r  p_2  =0.35  

c

The  p-value  is  p-value = 0.0072

The conclusion is

There is  sufficient evidence to conclude that the proportion of those indicating that  financial security is more fair in Feb 2010 is different from the proportion of  those indicating that financial security is more fair in Feb 2012.

Step-by-step explanation:

From the question we are told that

   The  sample size in 2012 is  n_1  =  1000

    The  number that indicated that their finance was more than fail is  k  =  410  

     The  sample  size in 2010  is  n_2  =  900

   The  number that indicated that their finance was more than fail is  u  =  315

     The  level of significance is  \alpha  =  0.05[/ex]The null hypothesis is  [tex]H_o :  p_1 = p_2

The  alternative hypothesis is   H_a :  p_1  \ne  p_2

Generally the sample proportion for  2012 is mathematically represented as

     \r  p_1  =  \frac{k}{n_1}

=>   \r  p_1  =  \frac{410}{1000}

=>   \r  p_1  =0.41

Generally the sample proportion for  2010 is mathematically represented as

      \r  p_2  =  \frac{u}{n_2}

=>   \r  p_2  =  \frac{315}{900}

=>   \r  p_2  =0.35    

Generally the pooled sample proportion is mathematically represented as

      \r p =  \frac{k + u }{n_1 + n_2}

=>     \r p =  \frac{410 + 315 }{1000+ 900}

=>      \r p =  0.3816

Generally the test statistics is mathematically represented as

     z =  \frac{( \r p_1 - \r p_2 ) - 0}{\sqrt{\r p (1 - \r p ) ( \frac{1}{n_1} +\frac{1}{n_2} )}  }

 z =  \frac{( 0.41 -0.35 ) - 0}{\sqrt{0.3816 (1 - 0.3816 ) ( \frac{1}{1000} +\frac{1}{900} )}  }    

 

 z =  \frac{( 0.41 -0.35 ) - 0}{\sqrt{0.3816 (1 - 0.3816 ) ( \frac{1}{1000} +\frac{1}{900} )}  }

   z  =  2.688

Generally the p- value  is mathematically represented as  

      p-value = 2 P(Z >2.688  )

From the z -table  

      P(Z > 2.688) = 0.0036

So  

      p-value = 2 *0.0036

        p-value = 0.0072

So from the p-value  obtained we see that p-value  <  \alpha so we reject the null hypothesis

Thus there is  sufficient evidence to conclude that the proportion of financial security is more fair in Feb 2010 is different from the proportion of financial security is more fair in Feb 2012.

5 0
3 years ago
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