Arc AD=98 and
I need help with both problems below
1 answer:
Answer:
arc DC = 64
angle DCQ = 32
Step-by-step explanation:
Hello There!
The circumference of a normal circle is 360
Given that arc AD = 98 and having found arc ABC we can find arc DC by subtract the known arcs from 360
360 - 98 - 198 = 64
Hence arc DC = 64
The problem wants us to find angle DCQ having found arc DC
Remember like stated before an included angle is equal to 1/2 its opposite arc
64/2=32
so angle DCQ = 32
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