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luda_lava [24]
2 years ago
9

What is the HCF of 1280 and 630

Mathematics
1 answer:
tatuchka [14]2 years ago
4 0

Given:

The two numbers are 1280 and 630.

To find:

The HCF of the given numbers.

Solution:

First write the given numbers in prime factorization form.

1280=2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 5

630=2\cdot 3\cdot 3\cdot 5\cdot 7

Now the product of all the common prime factors is known as the HCF of 1280 and 630.

HCF=2\cdot 5

HCF=10

Therefore, the HCF of 1280 and 630 is 10.

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Please help with 13 14 15 16
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The domain and the range for the relations are given as follows:

  • 13. Domain x ∈ R, range y ∈ R.
  • 14. Domain {x ∈ Z| -4 ≤ x ≤ 4 and x is even} , range y ∈ {y ∈ Z| -1 ≤ y ≤ 4}.
  • 15. Domain {x ∈ Z| -4 ≤ x ≤ 1} , range y ∈ {y ∈ Z| -4 ≤ y ≤ 1}.
  • 16. Domain x ∈ R, range y ∈ R.

<h3>What are the domain and range of a function?</h3>

  • The domain of a function is the set that contains all possible input values. Hence, in a graph, the domain is given by the values of x.
  • The range of a function is the set that contains all possible output values. Hence, in a graph, the domain is given by the values of y.

For items 13 and 16, the functions are continuous, hence it is over the real numbers, and both the domain and range are all real values.

For items 14 and 15, the functions are discrete, hence it is over the integer numbers, and the domain is composed by the values assumed by x and the range is composed by the values assumed by y.

More can be learned about domain and range at brainly.com/question/10197594

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