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vfiekz [6]
3 years ago
6

If the measure of angle is θ is 7pi/4 , which statements are true?

Mathematics
2 answers:
Hoochie [10]3 years ago
8 0

Answer:

\checkmark \sin\theta=-\frac{\sqrt{2}}{2}

\checkmark \tan \theta = -1

\checkmark The measure of the reference angle is 45^{\circ}

Step-by-step explanation:

The reference angle of an angle is the magnitude of the smallest angle it makes with the x-axis. In this case, we have 360-315=\boxed{45^{\circ}} (*Note: \frac{7\pi}{4}=315^{\circ}, use \pi=180^{\circ} to convert to degrees)

liubo4ka [24]3 years ago
5 0

Step-by-step explanation:

Convert 7π/4 to degrees

You'll have 315°

Reference angle is the angle that a given angle makes with the abscissa or x-axis.

360-315 = 45°

THE MEASURE OF THE REFERENCE ANGLE IS 45°

C and D are correct also

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The sum of two positive integers, a and b, is at least 30. The difference of the two integers is at least 10. If b is the greate
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a + b ≥ 30,  b ≥ a + 10, the system of inequalities could represent the values of a and b

option A

<u>Step-by-step explanation:</u>

Here we have , The sum of two positive integers, a and b, is at least 30. The difference of the two integers is at least 10. If b is the greater integer, We need to find which system of inequalities could represent the values of a and b . Let's find out:

Let two numbers be a and b where b>a . Now ,

  • The sum of two positive integers, a and b, is at least 30

According to the given statement we have following inequality :

⇒ a+b\geq 30

  • The difference of the two integers is at least 10

According to the given statement we have following inequality :

⇒ b-a\geq 10

⇒ b-a+a\geq 10 +a

⇒ b\geq 10 +a

Therefore , Correct option is A) a + b ≥ 30,  b ≥ a + 10

8 0
3 years ago
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Consider this sphere inside the cylinder. Which statements are true? Check all that apply. NEED HELP ASAP​
-Dominant- [34]

Option A: The height of the cylinder is equal to the diameter of the sphere.

Option C: The radius of the sphere is half the height of the cylinder.

Option E: The volume of the sphere is two-thirds the volume of the cylinder.

Solution:

The sphere is inside the cylinder.

Let r be the radius of the sphere.

Option A: The height of the cylinder is equal to the diameter of the sphere.

The sphere is fully occupied the cylinder.

If we draw the vertical line through enter of the sphere, which is equal to the height of cylinder.That is h = d. It is true.

Option B: The height of the cylinder is two times the diameter of the sphere.

That is h = 2d. From the above option, we know that h = d.

So, it is not true.

Option C: The radius of the sphere is half the height of the cylinder.

we know that diameter = 2 × radius (d = 2r)

From option A, we have h = d.

Substitute d = 2r, we get

⇒ h = 2r

Divide by 2 on both sides, we get

$\Rightarrow \frac{h}{2}=r

Therefore, it is true.

Option D: The diameter of the sphere is equal to the radius of the cylinder.

It is not true, because diameters of both cylinder and sphere are equal.

Option E: The volume of the sphere is two-thirds the volume of the cylinder.

Radius of cylinder and sphere = r

Height of cylinder h = 2r (by option C)

Volume of cylinder = Volume of sphere

  $\Rightarrow \pi r^2 h = \frac{4}{3} \pi r^3 (formula)

$\Rightarrow \pi r^2 (2r) = \frac{2\times2}{3} \pi r^3

$\Rightarrow 2 \pi r^3= \frac{2}{3} \times 2\pi r^3

Hence it is true.

Option A, option C and option E are true.

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The answer is equation
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An angelfish was 1 1/2 inches long when it was bought. Now it is 2 1/3 inches long.
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A)

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Now, the length of angelfish = 2 \frac{1}{3} inches

We have to determine the grown length of angelfish

=  2 \frac{1}{3} -  1 \frac{1}{2}

= \frac{7}{3}- \frac{3}{2}

LCM of '2' and '3' is '6',

= \frac{14-9}{6}

= \frac{5}{6} inch

Therefore, the angelfish has grown by \frac{5}{6} inch.

B)

We have to determine the increased length of angelfish in feet.

Since 1 inch = \frac{1}{12} foot

So, \frac{5}{6} inch = \frac{5}{6} \times \frac{1}{12} = \frac{5}{72}

= 0.069 foot.

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