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3 years ago

-6x - 14 > 10 what is the answer to this problem, please helt

Mathematics

1 answer:

rewona [7]3 years ago

5 0

Answer:

Inequality Form:

x < - 4

Interval Notation:

( − ∞ , − 4 )

Step-by-step explanation:

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Four times a number, added to the sum of the number and three

BlackZzzverrR [31]

Answer:

Yup! Great Job!

Step-by-step explanation:

3 0

3 years ago

A small cube has the volume shown. Its side length is 1.5 in less than a second larger cube. What is

eduard

The volume of the larger cube is 227 inches cube.

<h3 /><h3 /><h3>Volume of a cube is describe below:</h3>

v = L³

where

L = length

The small cube has the following volume:

v = 95 in³

Let

The side length of the small cube = x

Therefore,

95 = x³

x = ∛95

x = 4.56290264

x ≈ 4.6

Its side length is 1.5 inches less than a second larger cube. Therefore,

length of larger length cube = (x + 1.5 )inches = 4.6 + 1.5 = 6.1 inches

Therefore, the volume of the larger cube can be found as follows:

Volume = 6.1³

volume = 226.981

volume ≈ 227 inches³

learn more on cubes here:brainly.com/question/2671825?referrer=searchResults

6 0

3 years ago

Help!!!! Will give Brainly

uranmaximum [27]

Answer:

Point B represents the location of

$\sqrt{20}$

Step-by-step explanation:

As the value of under root 16 is 4 and the value of under root 25 is 5

So the location of under root 20 will be in between 4 and 5 on the number line

.

Hope it helps

4 0

3 years ago

Read 2 more answers

The cost of renting a community center is $100, with an additional cost of $10 per guest.

Rina8888 [55]

Answer:

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Help with spheres! I don't have to do question 3

Katena32 [7]

Question 1.

$d:$ diameter of the sphere

$r:$ radius of the sphere:

As we know,

$r=\dfrac{d}{2}\\ \\ r=\dfrac{15}{2}~\mathrm{in}$

Formula for the volume of a sphere, given its radius:

$V=\dfrac{4\pi r^{3}}{3}\\ \\ \\ V=\dfrac{4\pi\cdot (\frac{15}{2})^{3}}{3}\\ \\ \\ V=\dfrac{4\pi}{3}\cdot \dfrac{15^{3}}{8}\\ \\ \\ V=\dfrac{\diagup\!\!\!\! 4 \pi}{3}\cdot \dfrac{(3\cdot 5)^{3}}{\diagup\!\!\!\! 4\cdot 2}\\ \\ \\ V=\dfrac{\pi}{3}\cdot \dfrac{3^{3}\cdot 5^{3}}{2}\\ \\ \\ V=\dfrac{\pi}{\diagup\!\!\!\! 3}\cdot \dfrac{\diagup\!\!\!\! 3\cdot 3^{2}\cdot 5^{3}}{2}\\ \\ \\ V=\pi \cdot \dfrac{9\cdot 125}{2}\\ \\ \\ \boxed{\begin{array}{c} V=\dfrac{1\,125\pi}{2}\mathrm{~in^{3}} \end{array}}$

Question 2.

$r=6.8~\mathrm{ft}$

The volume of a hemisphere is given by

$V=\dfrac{2\pi r^{3}}{3}\\ \\ \\ V=\dfrac{2\pi\cdot (6.8)^{3}}{3}\\ \\ \\ V=\dfrac{2\pi\cdot 314.432}{3}\\ \\ \\ V \approx \dfrac{2*3.14*314.432}{3}\\ \\ \\ \boxed{\begin{array}{c} V \approx 658,2\mathrm{~ft^{3}} \end{array}}$

6 0

3 years ago