Let x = the first number
y = the second number
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First: set up the equations.
Four times a first number: 4x
Decreased by a second number: - y
Is 4: = 4
4x - y = 4.
The first number increased by: x +
three times the second number: 3y
is -25: = -25
x + 3y = -25.
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You can make your system of equations now.
4x - y = 4
x + 3y = -25
I would use substitution to solve these.
To do substitution, isolate a variable first, in one of the equations. I would probably isolate x in the second equation.
x + 3y = -25
x = -25 - 3y
Now, you can substitute -25 - 3y into 4x - y = 4, as x.
4x - y = 4
4(-25 - 3y) - y = 4
Now just solve for y.
-100 - 12y - y = 4
-13y = 104
y = -8
Now, you can put -8 as y into one of the original equations, I'll just use 4x - y = 4.
4x - y = 4
4x - (-8) = 4
4x + 8 = 4
4x = -4
x = -1
So the first number is -1, and the second -2.
Y=3x-23
.
Hope this helps :)
Answer:
Thus, the coffee shop is willing to supply 6 pounds per week at a price of $4 per pound.
Step-by-step explanation:
We are given the following information in the question:
The marginal price per pound (in dollars) is given by:
where x is the supply in pounds.
The coffee shop is willing to supply 9 pounds per week at a price of $7 per pound.
Thus, we are given that
P(9) = 7
Putting the values, we get,
Now, we have to find how many pounds it would be willing to supply at a price of $4 per pound.
P(x) = 4
Thus, the coffee shop is willing to supply 6 pounds per week at a price of $4 per pound.
3(1+2)
3+6
9 ( the answer is nine)
first you divide six and two then use the distributive property to multiply three and one and three and two, then add three and six to get nine.
